The 100% relative humidity in the winter feel nothing like 100% in summer because it depends on "the saturation of the temperature".
<u>Explanation:</u>
Temperature really makes a big difference. Even once warm, a cold winter air produces much less humidity than summer heat. One cubic unit of air needs 0.001 ounces of water to saturate it, to elevate its ratio to one hundred per cent.
Nevertheless, it takes 0.022 ounces of water to saturate the one cubic unit of air once the temperature is eighty, which is twenty-two times that amount of water. Air with a humidity of one hundred percent at eighty degrees holds twenty-two times as much water as air at zero with humidity at one hundred percent.
No it isn't. (Unless you connect it backwards.)
If the primary has 10 turns and the secondary has 70 turns,
then the voltage that appears across the secondary is
7 times the voltage that you feed to the primary.
If you're 'exciting' the primary with 170 volts, then you need
to be cautious around the secondary terminals, because there's
1,190 volts there !
If you want to use your transformer in a step-down configuration,
you can certainly connect it up the other way around.
Feed the 170 volts to the winding with 70 turns. You've reversed
the labels 'primary' and 'secondary', and that's OK. The voltage
at the terminals of the 10-turn winding will be (170/7) = 24.3 volts.
Overloading
Explanation:
The reason reason why the mcb of rupa's room keeps tripping is due to the fact that excessive current has being supplied to his room.
MCB stands for a miniature circuit breaker.
A miniature circuit breaker opens up the electrical circuit by switching it off when there is overloading or faulty connections.
- A MCB helps to control the flow of current and it is designed to hand certain limits of electrical voltage.
- If the MCB keeps tripping, it suggests a surge in current supplied, overloading or probably a faulty connection.
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Answer:
12 m/s
Explanation:
First, find the time it takes for the ball to fall 2.0 m.
y = y₀ + v₀ t + ½ at²
0 = 2.0 + (0) t + ½ (-9.8) t²
0 = 2 − 4.9t²
t = 0.639
Find the velocity needed to travel 7.8 m in that time.
x = x₀ + v₀ t + ½ at²
7.8 = 0 + v₀ (0.639) + ½ (0) (0.639)²
7.8 = 0.639 v₀
v₀ = 12.2
Rounded to two significant figures, the initial velocity is 12 m/s.
