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Charra [1.4K]
3 years ago
15

How many miles of H2SO4 are present in 1.63 liters of a 0.954 M solution

Chemistry
1 answer:
soldi70 [24.7K]3 years ago
5 0

Answer:

1.555 moles

Explanation:

Mass of sulfuric acid is 98.079g/mol

One liter of 0.954 solution has 0.954 mols

1.63 liters will have 0.954x1.63 = 1.555moles

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What is a possible cause of a large percentage of error in an experiment where mgo is produced from the combustion of magnesium?
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In 1928, 47.5 g of a new element was isolated from 660 kg of the ore molybdenite. the percent by mass of this element in the ore
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A solution is made by dissolving 10.20 grams of glucose (C6H12O6) in 355 grams of water. What is the freezing point depression o
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Answer:

0.297 °C

Step-by-step explanation:

The formula for the <em>freezing point depression </em>ΔT_f is

ΔT_f = iK_f·b

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       glucose(s) ⟶ glucose(aq)

1 mole glucose ⟶ 1 mol particles     i = 1

Data:

Mass of glucose = 10.20 g

  Mass of water = 355 g

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(a) <em>Moles of glucose </em>

n = 10.20 g × (1 mol/180.16 g)

  = 0.056 62 mol

(b) <em>Kilograms of water </em>

m = 355 g × (1 kg/1000 g)

   = 0.355 kg

(c) <em>Molal concentration </em>

b = moles of solute/kilograms of solvent

  = 0.056 62 mol/0.355 kg

  = 0.1595 mol·kg⁻¹

(d) <em>Freezing point depression </em>

ΔT_f = 1 × 1.86 × 0.1595

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3 years ago
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