If gravity between the Sun and Earth suddenly vanished, Earth would continue moving in

Physics

1 answer:

Ksenya-84 [330]3 years ago

6 0

Answer:

Earth would continue moving by uniform motion, with constant velocity, in a straight line

Explanation:

The question can be answered by using Newton's first law of motion, also known as law of inertia, which states that:

"an object keeps its state of rest or of uniform motion in a straight line unless acted upon by an external net force different from zero"

This means that if there are no forces acting on an object, the object stays at rest (if it was not moving previously) or it continues moving with same velocity (if it was already moving) in a straight line.

In this problem, the Earth is initially moving around the Sun, with a certain tangential velocity v. When the Sun disappears, the force of gravity that was keeping the Earth in circular motion disappears too: therefore, there are no more forces acting on the Earth, and so by the 1st law of Newton, the Earth will continue moving with same velocity v in a straight line.

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Are the two expressions equvalent 7(8x+5) and 48x + 35

Evgesh-ka [11]

Yes they are equivalent because 7x5=35 and 8x x 5=48x

4 0

3 years ago

How much kinetic energy does a moving 100 kg object have if it is moving at 5 m/s?

Vesnalui [34]

Answer:

The object has 1250 Joules of Kinetic Energy.

Explanation:

Kinetic Energy = $\frac{1}{2}$ mass*velocity²

KE = $\frac{1}{2}$ mv²

KE = $\frac{1}{2}$ (100kg)(5m/s)²

KE = $\frac{1}{2}$ (100kg)(25m/s²)

KE = 1250 $\frac{kg}{m/s^2}$

KE = 1250J

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3 years ago

A block slides down a frictionless inclined ramp. If the ramp angle is 17.0° and its length is find the speed of the block as it

SashulF [63]

Answer:

$2.4\sqrt{L}$ where L is the length of the ramp

Explanation:

Let L (m) be the length of the ramp, and g = 9.81 m/s2 be the gravitational acceleration acting downward. This g vector can be split into 2 components: parallel and perpendicular to the ramp.

The parallel component would have a magnitude of

$gsin\theta = 9.81 sin17^o = 2.87 m/s^2$

We can use the following equation of motion to find out the final velocity of the book after sliding L m:

$v^2 - v_0^2 = 2a\Delta s$

where v m/s is the final velocity, $v_0$ = 0m/s is the initial velocity when it starts from rest, a = 2.87 m/s2 is the acceleration, and $\Delta s = L$ is the distance traveled: