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3 years ago

If gravity between the Sun and Earth suddenly vanished, Earth would continue moving in

Physics

1 answer:

Ksenya-84 [330]3 years ago

6 0

Answer:

Earth would continue moving by uniform motion, with constant velocity, in a straight line

Explanation:

The question can be answered by using Newton's first law of motion, also known as law of inertia, which states that:

"an object keeps its state of rest or of uniform motion in a straight line unless acted upon by an external net force different from zero"

This means that if there are no forces acting on an object, the object stays at rest (if it was not moving previously) or it continues moving with same velocity (if it was already moving) in a straight line.

In this problem, the Earth is initially moving around the Sun, with a certain tangential velocity v. When the Sun disappears, the force of gravity that was keeping the Earth in circular motion disappears too: therefore, there are no more forces acting on the Earth, and so by the 1st law of Newton, the Earth will continue moving with same velocity v in a straight line.

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Science Mixtures Question( giving brainly, thanks, and rank of 5 stars.)

vazorg [7]

Answer:

Condensation

Explanation:

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3 years ago

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A 120 V potential difference is applied to a space heater that dissipates 674 W during operation. (a) What is its resistance dur

Annette [7]

Answer:

(a) 21.36 ohms

(b) 5.62 A

Explanation:

Parameters given:

Potential difference, V = 120 V

Power, P = 674 W

(a) Power is given as:

P = V²/R

Where R is resistance

=> R = V²/P

R = 120²/674

R = 14400/674

R = 21.36 ohms

(b) Power is also given as:

P = I*V

Where I = Current (time rate of flow of Electric charge)

=> I = P/V

I = 674/120

I = 5.62 A

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3 years ago

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Chef tom works in a very busy restaurant. he cooks for 100's of people each night. why chef tom would use a copper pot instead o

Gala2k [10]

<span>the copper pot heats up faster because it is a better conductor</span>

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3 years ago

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The coefficient of linear expansion of iron is 1.0 × 10−5 per C◦ . The surface area of an iron cube, with an edge length of 5.0

Allushta [10]

The linear expansion of iron is a = 1× 10∧ -5 /°C
Length edge is 5cm
Initial surface area of cube A = 6L ∧²
= 150cm∧²
The edge length of cube after being heated from
10°C to 60°C is
L = L[I +a dt] where the dt is = 60-10 = 50°C
5.0025cm
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A' = 6L' ∧²
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3 years ago

The three vectors in Fig. 3-33 have magnitudes a = 3.00 m, b = 4.00 m, and c = 10.0 m and angle θ = 30.0°. What are

aliya0001 [1]

Answer:

a) $a_{x} =3$ b) $a_{y} =0$

c) $b_{x} =3.46$ d) $b_{y} =2$

e) $c_{x} =0$ f) $c_{y} =10$

g) p = -5.77 h) q=5

Explanation:

Diagram for given question is attached below in fig 1

for vector $\vec{a}$

θ = 0°

$a_{x} = 3 cos (0)\\a_{x} = 3\\a_{y} = 3 sin (0)\\a_{y} = 0$

for vector $\vec{b}$

θ = 30°

$b_{x} = 4 cos (30)\\b_{x} = 3.46\\b_{y} = 4 sin (30)\\b_{y} = 2$

for vector $\vec{c}$

θ = 90°

$c_{x} = 10 cos (90)\\c_{x} = 0\\c_{y} = 10 sin (90)\\c_{y} = 10$

$\vec{c} = p\vec{a} + q\vec{b}$

$c =c_{x} \hat{i} + c_{y}\hat{j}\\as a_{y} =0\\c_{x} \hat{i} + c_{y}\hat{j} = pa_{x} \hat{i} +q(b_{x} \hat{i} +b_{y} \hat{j} )\\c_{x} \hat{i} = pa_{x} \hat{i} +qb_{x} \hat{i}\\c_{y}\hat{j} =qb_{y}\hat{j}$

$q=\frac{c_{y}}{b_{y}} \\q=\frac{10}{2}\\q=5$

$c_{x} \hat{i} = pa_{x} \hat{i} +qb_{x} \hat{i}\\0 = p(3) + (5)(3.46)\\p = -5.77$

5 0

3 years ago