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Solnce55 [7]
4 years ago
12

Suppose 6 quarts of a solution that is 45% antifreeze is mixed with 2 quarts of a solution that is 19% antifreeze.

Chemistry
1 answer:
Sidana [21]4 years ago
7 0
6+2=8 quarts of a new solution

0.45*6  - quarts  antifreeze in <span>a solution that is 45% antifreeze
0.19*2  - </span>quarts  antifreeze in a solution that is 19% antifreeze

x- concentration of a new solution
8x -  quarts  antifreeze in a new solution 

0.45*6 + 0.19*2 = 8x
3.08=8x
x= 0.385 =38.5 %

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