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Pani-rosa [81]
3 years ago
7

Free body diagram for a 4kg

Physics
1 answer:
Svetradugi [14.3K]3 years ago
4 0
999999999999999999999999999999999999999999999999999999
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Which of the following is same dimension quantity?
hram777 [196]

Answer:

Find the dimension of each and every quantity in all the options to check whether they are the same or not. We can use any one formula of each identity to find its dimension.

Complete step by step solution:

To find the dimension of a quantity, we can use any formula related to that quantity but we will use the easiest ones to save time.

Force-

from Newton’s law of motion,

F=maF=ma

Dimension of force =[M][LT−2]=[MLT−2]=[M][LT−2]=[MLT−2]

Work done-

W=F×sW=F×s

Dimension of work=[MLT−2][L]=[ML2T−2]=[MLT−2][L]=[ML2T−2]

Momentum-

p=mvp=mv

Dimension of momentum=[M][LT1]=[MLT−1]=[M][LT1]=[MLT−1]

Impulse-

I=F×tI=F×t

Dimension of impulse=[MLT−2][T]=[

3 0
3 years ago
Is there any machine that is 100% efficient? why?why not
denis-greek [22]

Answer:

No, it's not there.

Explanation:

For a machine to be 100% efficient, it has to be with an output which is equal to its input. But machines have an out put less than an input, hence efficiency below 100%.

7 0
3 years ago
How can you show that pressure increases with the increase of force?​
Julli [10]

Answer:

...........................

7 0
3 years ago
Read 2 more answers
Bits of paper are attracted to an electrified comb or rod, even though they have nonet charge. How is this possible?
SashulF [63]

Explanation:

An electrified comb is charged comb ( let say by running it through the hair) and when it is brought in the proximity of  pieces of paper, the pieces tend to cling to it. This happens because the charged comb induces an opposite charge in the paper pieces and as opposite charges attract each other, the pieces are clinged.

7 0
4 years ago
Water (density = 1 ´ 103 kg/m3) flows at 10 m/s through a pipe with radius 0.030 m. the pipe goes up to the second floor of the
Hatshy [7]

density of water = 1000 kg/m^3

velocity of flow = 10 m/s

radius of pipe = 0.030 m

Height of second floor = 2 m

Now we can use here Bernuoli's Equation to find the speed of water flow at second floor

P_1 + 1/2\rho v_1^2 + \rho g h_1= P_2 + 1/2 \rho v_2^2 + \rho g h_2

P + 1/2 * 1000 * 10^2 + 1000* 9.8 * 0 = P + 1/2 * 1000 * v^2 + 1000*9.8*2

v = 7.8 m/s

Now in order to find the radius of pipe we can use equation of continuity

A_1 v_1 = A_2 v_2

\pi *0.030^2 * 10 = \pi * r^2 * 7.8

r = 0.034 m

So radius of pipe at second floor is 0.034 meter

3 0
3 years ago
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