1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
N76 [4]
3 years ago
7

The ground state energy of an oscillating electron is 1.23 eV. How much energy must be added to the electron to move it to the t

hird excited state? The fourth excited state?
Physics
1 answer:
Vikki [24]3 years ago
5 0

Answer:

  • The energy that must be added to the electron to move it to the third excited state is  -1.153 eV
  • The energy that must be added to the electron to move it to the fourth excited state is  -1.181 eV

Explanation:

Given;

Energy of electron in ground state (n = 1 ) = 1.23 eV

E₁ = 1.23 eV

Eₙ = E₁ /n²

where;

E₁ is the energy of the electron in ground state

n is the energy level,

For third excited state, n = 4

E₄ = E₁ /4²

E₄ = (1.23 eV) / 16

E₄ = 0.077 eV

Change in energy level, = E₄ - E₁ = 0.077 eV - 1.23 eV = -1.153 eV

The energy that must be added to the electron to move it to the third excited state is  -1.153 eV

For fourth excited state, n = 5

E₅ = E₁ /5²

E₄ = (1.23 eV) / 25

E₄ = 0.049 eV

Change in energy level, = E₅ - E₁ = 0.049 eV - 1.23 eV = -1.181 eV

The energy that must be added to the electron to move it to the fourth excited state is  -1.181 eV

You might be interested in
A force on a particle depends on position such that F(x) = (3.00 N/m2)x2 + (6.00 N/m)x for a particle constrained to move along
Pachacha [2.7K]

Answer:

The work done by a particle from x = 0 to x = 2 m is 20 J.

Explanation:

A force on a particle depends on position constrained to move along the x-axis, is given by,

F(x)=(3\ N/m^2)x^2+(6\ N/m)x

We need to find the work done on a particle that moves from x = 0.00 m to x = 2.00 m.

We know that the work done by a particle is given by the formula as follows :

W=\int\limits {F{\cdot} dx}

W=\int\limits^2_0 {(3x^2+6x){\cdot} dx} \\\\W={(x^3}+3x^2)_0^2\\\\\W={(2^3}+3(2)^2)\\\\W=20\ J

So, the work done by a particle from x = 0 to x = 2 m is 20 J. Hence, this is the required solution.

3 0
3 years ago
Read 2 more answers
A horizontal force of 675 N is needed to overcome the force of static friction between a level floor and a 300-kg crate. What is
White raven [17]

Explanation:

Below is an attachment containing the solution.

8 0
2 years ago
10,500 J of GPE, weight 539 N, how tall is the hill you are sitting on?
maks197457 [2]

Answer:

19.48 m

Explanation:

Gravitational potential energy = mgh

Current weight = 539 N

Weight = mg = 539 N

Mass x Acceleration = 539 N

Mass x 9.81 = 539

Mass = 54.94 kg

Gravitational potential energy = mgh = 10500 J

                    54.94 x 9.81 x h = 10500

                               h = 19.48 m

Height of sitting = 19.48 m

6 0
2 years ago
A manometer is used to measure the air pressure in a tank. the fluid used has a specific gravity of 1.25, and the differential h
BartSMP [9]
Specific Gravity of the fluid = 1.25 
Height h = 28 in
 Atmospheric Pressure = 12.7 psia
 Density of water = 62.4 lbm/ft^3 at 32F
 Density of the Fluid = Specific Gravity of the fluid x Density of water = 1.25 x 62.4
 Density of the Fluid p = 78 lbm/ft^3
 Difference in pressure as we got the differential height, dP = p x g x h  dP = (78 lbm/ft^3) x (32.174 ft/s^2) x (28/12 ft) [ 1 lbf / 32.174 ft/s^2] [1 ft^2 /
144in^2]
 Difference in pressure = 1.26 psia
 (a) Pressure in the arm that is at Higher 
 P = Atmospheric Pressure - Pressure difference = 12.7 - 1.26 = 11.44 psia
 (b) Pressure in the tank that is at Lower
 P = Atmospheric Pressure + Pressure difference = 12.7 + 1.26 = 13.96psia
4 0
3 years ago
Problem:
Mars2501 [29]
I do have a couple ideas and tips that may help you win. I don’t know how the guidelines are set up so if the ideas won’t be helpful I apologize.

First off put some ice cubes in the container then sprinkle salt on them, The reaction will create an effect and be super cold.


Another idea would be to get some dry ice if you able to, This will freeze it solid within seconds.


The last idea combines the the first. Take a bowl and fill it with with water and ice (Make sure the bowl is insulated) add a small handful of salt into the bowl, Put your drink into the cooler and before shutting stir then well then close and wait for the amount of time left, Your should have a cold water bottle.


I hoped this helped you out and I hope you also win the contest.
8 0
3 years ago
Other questions:
  • A star has a spectrum with lines indicating the presence of ionized helium. This star should be classified as a(n) _____ type st
    9·2 answers
  • Water is a compound because it?
    15·1 answer
  • When the moving sidewalk at the airport is broken, as it often seems to be, it takes you 44 s to walk from your gate to baggage
    13·1 answer
  • A bottle with a volume of 193 U. S. fluid gallons is filled at the rate of 1.9 g/min. (Water has a density of 1000 kg/m3, and 1
    13·1 answer
  • What is the main difference between a generator and an electric motor?
    10·2 answers
  • The chemical equation for the decomposition of potassium chlorate into potassium chloride and oxygen gas is
    13·1 answer
  • How many grams are in 5 kilos​
    6·2 answers
  • Would a rougher or smoother object absorb thermal energy faster? Why? Give an example.
    6·1 answer
  • Two rubber bullets (each of the same mass) are fired at the same velocity towards two different blocks of equal mass. One block
    15·1 answer
  • Can someone please answer this, ill give you brainliest and your earning 50 points.
    11·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!