Answer:

Explanation:
The work function of the metal corresponds to the minimum energy needed to extract a photoelectron from the metal. In this case, it is:

So, the energy of the incoming photon hitting on the metal must be at least equal to this value.
The energy of a photon is given by

where
h is the Planck's constant
c is the speed of light
is the wavelength of the photon
Using
and solving for
, we find the maximum wavelength of the radiation that will eject electrons from the metal:

And since
1 angstrom = 
The wavelength in angstroms is

Answer:
what help you need?????????
600/3 = 200
the slope is 200m/min
OR
600/ (3/60) =
600 x 60/3 =
600 x 20 = 12,000 meters per hour
Answer:
Capacitance of the second capacitor = 2C
Explanation:

Where A is the area, d is the gap between plates and ε₀ is the dielectric constant.
Let C₁ be the capacitance of first capacitor with area A₁ and gap between plates d₁.
We have

Similarly for capacitor 2

Capacitance of the second capacitor = 2C
Answer:
A I think
Explanation:
because what is the most frequency a because it has more frequency I think I'm not that sure