The answer to this question is false
The strength of the electric field on the point charge at this distance will be 4000 V/m.
<h3>What is the strength of the electric field?</h3>
The strength of the electric field is the ratio of electric force per unit charge.
The given data in the problem is;
Qis the unit charge = 4.0 × 10⁻⁶ C
E is the strength of the electric field
R is the distance from point charge = 3 m
The strength of the electric field is;

Hence, the strength of the electric field on the point charge at this distance will be 4000 V/m.
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Answer:
Object A will get 200 & object B will get 400 Potential Energy
Explanation:
Potential Energy = mgh (mass x gravity x height)
For Object A :-
2 (mass) x 10 (approx gravity on Earth) x 10 (distance/height)
= 200
For Object B :-
4 x 10 x 10
= 400
Hence Object B will have High Potential Force than A.
Hope it helps. Thanks