Answer:
the tension in each side of the cable is 3677.57 N
Explanation:
given data
traffic light = 20 kg
cable between two poles = 30 m
sag in the cable = 0.40 m
solution
by the free body diagram
tan θ = 
.............1
θ = 1.527 °
and
tension = mg
The net force is along x - axis is express as
T2 cosθ = T1 cosθ .................2
so T2 - T1 ..............3
and
when we take it along y axis that is express as
( T1 + T2) sinθ = mg ...................4
so by equation 3 we put here
2 × T1 sin(1.527) = 20 × 9.8
T1 = 3677.57 N
Answer: cost to implement conservation policies
environmental implications
benefit versus the cost
Explanation:
The conservation policies involves certain instructions which are required to be followed by the human society at all levels so as to conserve resources and protect them for future. The following are the issues which government should be consider before passing the conservation policies this includes:
1. cost to implement conservation policies
: The procedure and expenditure for the implementation of the policies should be under control of the desired budget so that the plan can be efficiently executed.
2.environmental implications
: The government should be concerned about the implication of the policies on the environment. For example the preservation of an endangered species in control condition from an ecosystem can disturb the overall balance of an ecosystem.
3.benefit versus the cost: The government should concern before expending on the implementation of the policies the benefits and costs of the desired policies.
Answer:
P = 238475 N
Q = 181125
Explanation:
From the diagram attached below,
For the bridge to be at equilibrium,
Sum of upward force = sum of downward force
P+Q = 400000+19600
P+Q = 419600.................. Equation 1
Taking moment about support A
sum of clockwise moment = sum of anti clockwise moment.
400000(10-3)+19600(8-3) = Q(20-6)
2800000+98000 = 16Q
2898000 = 16Q
Q = 2898000/16
Q = 181125 N.
Substitute the value of Q into equation 1
P+181125 = 419600
P = 419600-181125
P = 238475 N.
Hence, support A exert a force of 238475 N and support B exert a force of 181125 N
