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g100num [7]
2 years ago
10

A satellite orbiting Earth at a velocity of 3700 m/s collides with a piece of

Physics
1 answer:
Gekata [30.6K]2 years ago
7 0

Answer: B

Explanation:

You can use the conservation of momentum, under the assumption that no mass was lost when the collision occurred. The initial momentum of the system must equal the final momentum of the system. Our system is the region including, and only including, the satellite and the space debris. Classical momentum is defined as the product of mass and velocity:

p_i=p_f

m_1v_1_i+m_2v_2_i=m_1v_1_f+m_2v_2_f

Due to mass 1 equaling mass 2, we can factor these quantities out:

m(v_1_i+v_2_i)=m(v_1_f+v_2_f)

Cancel the mass term on both sides to get:

v_1_i+v_2_i=v_1_f+v_2_f

We have the initial and final velocities for everything besides the final velocity of the satellite. Plug everything in:

3700m/s+6000m/s=v_1_f+3700m/s

v_1_f=6000m/s

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A satellite that goes around the earth once every 24 hours iscalled a geosynchronous satellite. If a geosynchronoussatellite is
lesantik [10]

Answer:

35870474.30504 m

Explanation:

r = Distance from the surface

T = Time period = 24 h

G = Gravitational constant = 6.67 × 10⁻¹¹ m³/kgs²

m = Mass of the Earth =  5.98 × 10²⁴ kg

Radius of Earth = 6.38\times 10^6\ m

The gravitational force will balance the centripetal force

\dfrac{GMm}{R^2}=m\dfrac{v^2}{R}\\\Rightarrow v=\sqrt{\dfrac{GM}{R}}

T=\dfrac{2\pi r}{v}\\\Rightarrow T=\dfrac{2\pi r}{\sqrt{\dfrac{GM}{r}}}

From Kepler's law we have relation

T^2=\dfrac{4\pi^2r^3}{GM}\\\Rightarrow r^3=\dfrac{T^2GM}{4\pi^2}\\\Rightarrow r=\left(\dfrac{(24\times 3600)^2\times 6.67\times 10^{-11}\times 5.98\times 10^{24}}{4\pi^2}\right)^{\dfrac{1}{3}}\\\Rightarrow r=42250474.30504\ m

Distance from the center of the Earth would be

42250474.30504-6.38\times 10^6=\mathbf{35870474.30504\ m}

8 0
3 years ago
Two bicyclist, originally separated by a distance of 20 miles, are each traveling at a uniform speed of 10 miles per hour toward
Radda [10]

Answer:

D = 25 miles

Explanation:

To solve this problem, we just need to know how much time it took both bicyclists to collide and that will be the same amount of time that the bee flew at 25miles per hour. With those values we could calculate the distance it traveled.

Since both bicyclists collide, we know that Xa=Xb, so:

Xa = V*t = 10*t     and    Xb = 20 - V*t = 20 - 10*t

10*t = 20 - 10*t      Solving for t:

t = 1 hour  Now we can calculate the distance for the bee:

D = Vbee * t = 25 * 1 = 25 miles

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4 years ago
A concave mirror has a radius of curvature of 0.60 meter.
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3 years ago
Ice core samples are used to measure…
blsea [12.9K]

Answer:

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6 0
3 years ago
Read 2 more answers
A geosynchronous satellite moves in a circular orbit around the Earth and completes one circle in the same time T during which t
vodka [1.7K]

Answer:

   h = r- R   with   r = ∛ (G M T² / 4π²)

Explanation:

As the satellite interacts with the Earth, let's use the law of universal gravitation

            F = G m M / r²

Let's write Newton's second law

           F = m a

           a = v2 / r

   

          G m M / r² = m v² / r

          G M / r = v²

          r = G M / v²

Let's work on satellite speed, counting speed, so we use uniform speed expressions

          v = d / t

Let's look for the distance it travels in a complete orbit and its time is equal to one (1) day since the satellite is geosynchronous

           d = 2π r

           t = T = 1 day (24h / 1day) (3600s / 1h) = 86400 s

           v = 2 π R / T

Let's calculate

           r = G M (T / 2π r)²

           r = G M T² / 4π² r²

           r³ = G M T² / 4π²

           r = ∛ (G M T² / 4π²)

This distance (r) is measured from the center of the earth, let's get the height (h) from the planet's surface

          r = R + h

          h = r- R

3 0
3 years ago
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