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g100num [7]
2 years ago
10

A satellite orbiting Earth at a velocity of 3700 m/s collides with a piece of

Physics
1 answer:
Gekata [30.6K]2 years ago
7 0

Answer: B

Explanation:

You can use the conservation of momentum, under the assumption that no mass was lost when the collision occurred. The initial momentum of the system must equal the final momentum of the system. Our system is the region including, and only including, the satellite and the space debris. Classical momentum is defined as the product of mass and velocity:

p_i=p_f

m_1v_1_i+m_2v_2_i=m_1v_1_f+m_2v_2_f

Due to mass 1 equaling mass 2, we can factor these quantities out:

m(v_1_i+v_2_i)=m(v_1_f+v_2_f)

Cancel the mass term on both sides to get:

v_1_i+v_2_i=v_1_f+v_2_f

We have the initial and final velocities for everything besides the final velocity of the satellite. Plug everything in:

3700m/s+6000m/s=v_1_f+3700m/s

v_1_f=6000m/s

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Please help! the mass of an object is measured on a pan balance with a precision of 0.005 g and the recorded value of 128.01 g.
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Yes, these two objects have different masses.

<h3>How can we calculate that this statement is right ?</h3>

To calculate the precision of mass we are using the formula,

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For the second case we are given,

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For the second case \trianglem is 25.87 Kg.

For the two cases  \trianglem has different values, 25.47 Kg≠25.87 Kg.

Therefore we can conclude that, these two objects have different masses.

Learn more about Mass:

brainly.com/question/3187640

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