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Hitman42 [59]
3 years ago
9

Group 17 is called the halogen family, and the group to its right is called the noble gases. How are these elements alike and ho

w are they different?
 
Physics
1 answer:
vodka [1.7K]3 years ago
3 0

-The group 7 elements are also known as the halogens. They include fluorine, chlorine, bromine and iodine, which all have seven electrons in their outer shell.

-The noble gases make a group of chemical elements with comparable properties; under standard conditions, they are all odorless, colorless, monatomic gases with very low chemical reactivity. The six noble gases that occur naturally are helium, neon, argon, krypton, xenon, and the radioactive radon. FACT: They can also act like a glow stick.<span>[ID1] </span>

<span> [ID1]</span>

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Calculate the energy of a photon having a wavelength in thefollowing ranges.(a) microwave, with λ = 50.00 cmeV(b) visible, with
IgorLugansk [536]

(a) 2.5\cdot 10^{-6}eV

The energy of a photon is given by:

E=\frac{hc}{\lambda}

where

h=6.63\cdot 10^{-34}Js is the Planck constant

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\lambda is the wavelength

For the microwave photon,

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For the energy of the photon, we can use the same formula:

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For the visible light photon,

\lambda=500 nm = 5 \cdot 10^{-7}m

So the energy is

E=\frac{(6.63\cdot 10^{-34}Js)(3\cdot 10^8 m/s)}{5\cdot 10^{-7} m}=4.0\cdot 10^{-19} J

And converting into electronvolts,

E=\frac{4.0\cdot 10^{-19}J}{1.6\cdot 10^{-19} J/eV}=2.5 eV

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E=\frac{hc}{\lambda}

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\lambda=0.5 nm = 5 \cdot 10^{-10}m

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E=\frac{(6.63\cdot 10^{-34}Js)(3\cdot 10^8 m/s)}{5\cdot 10^{-10} m}=4.0\cdot 10^{-16} J

And converting into electronvolts,

E=\frac{4.0\cdot 10^{-16}J}{1.6\cdot 10^{-19} J/eV}=2500 eV

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