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vodka [1.7K]
3 years ago
8

When 24g of magnesium metal is heated in air, 40g of magnesium oxide is produced. What mass of magnesium would be needed in orde

r to produce 10g of magnesium oxide?
Chemistry
1 answer:
inysia [295]3 years ago
6 0

Answer: 6.1 g

Explanation:

between Mg and MgO theres a 1;1 MOLE RATIO

here's the balanced equation

2Mg + O2 ==> 2MgO

24g of magnesium is approximately 1 mole of magnesium so it produces 40 g of mgo which is also 1 mole of mgo thus 10/40 =0.25 moles of MgO so 0.25 moles of magnesium would be needed  which is approximately 6.1 g

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As methane burns, it reacts with oxygen and forms carbon dioxide and water. The balanced chemical equation below models this che
Elan Coil [88]

Explanation:

hope this helps please like and mark as brainliest

3 0
3 years ago
For a particular reaction, Δ H ∘ = 55.4 kJ ΔH∘=55.4 kJ and Δ S ∘ = 94.1 J/K. ΔS∘=94.1 J/K. Assuming these values change very lit
nadezda [96]

Answer:

The temperature at which the reaction changes from non-spontaneous to spontaneous is 588.735 K

Explanation:

The spontaneity of a reaction is determined by the change in Gibbs Free Energy, \Delta G^{0}.

\Delta G^{0} =\Delta H^{0} -T\Delta S^{0}

If \Delta G^{0} is greater than zero, then a reaction is feasible.

If \Delta G^{0} is less than zero, then a reaction is not feasible.

To determine the temperature at which the reaction changes from non-spontaneous to spontaneous, we should equate the \Delta G^{0} to zero.

We take \Delta G^{0}=0 as the limiting condition.

T=\frac{\Delta H^{0}}{\Delta S^{0}}=\frac{55.4\times10^{3}}{94.1}=588.735K

Therefore, the temperature is: 588.735K

7 0
4 years ago
Which statement about erosion is true? Most erosion occurs too slowly to observe. Most erosion occurs too quickly to observe, Er
olganol [36]

Answer:

Erosion can happen very quickly or very slowly.

e.g splash erosion occurs slowly while gulley erosion occurs very fast.

7 0
3 years ago
A hydrate is determined to be 45.43% water and 54.57% CoCl. Find the chemical formula and name for this hydrate. (*Hint - assume
sdas [7]

Answer : The chemical formula for the given compound is COCl_2.6H_2O

Explanation : Given,

If percentage are given then we are taking total mass is 100 grams.

So, the mass of each element is equal to the percentage given.

Mass of H_2O = 45.43 g

Mass of COCl_2 = 54.57 g

Molar mass of H_2O = 18 g/mole

Molar mass of COCl_2 = 129.9 g/mole

To formulate the chemical formula, we need to follow some steps:

Step 1: Converting the given masses into moles.

Moles of water =\frac{\text{Given mass of water}}{\text{Molar mass of water}}=\frac{45.43g}{18g/mole}=2.524moles

Moles of COCl_2 = \frac{\text{Given mass of }COCl_2}{\text{Molar mass of }COCl_2}=\frac{54.57g}{129.9g/mole}=0.4201moles

Step 2: Calculating the mole ratio of the given molecule.

For the mole ratio, we divide each value of the moles by the smallest number of moles calculated which is 0.4201 moles.

For H_2O = \frac{2.524}{0.4201}=6.00\approx 6

For Carbon = \frac{0.4201}{0.4201}=1

Step 3: Taking the mole ratio as their subscripts.

The ratio of COCl_2:H_2O = 1 : 6

The chemical formula for the given compound is (COCl_2)_1(H_2O)_6=COCl_2.6H_2O

Hence, the chemical formula for the given compound is COCl_2.6H_2O

7 0
4 years ago
3. The complex ion Co(H2O)6 2(aq) is pink when placed in solution. Addition of chloride ions creates an equilibrium with CoCl42-
mart [117]

Answer:

See explanation

Explanation:

When the complex ion Co(H2O)6 2+(aq) is placed in solution and chloride ions are added, the following equilobrium is set up;

  Co(H2O)62+(aq) + 4 Cl-(aq) <=> CoCl42-(aq) + 6 H2O(g)

Co(H2O)6 2+(aq) solution  is pink in colour while CoCl42-(aq) solution is blue in colour.

Since the solubility of CoCl42-(aq) is endothermic, heating the solution will move the equilibrium position towards the right (more CoCl42-(aq) is formed and the solution is blue in colour).

When the solution is cooled, more Co(H2O)62+(aq) is formed and the equilibrium position shifts towards the left and the solution becomes pink in colour.

6 0
3 years ago
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