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2 years ago

14

A luge and its rider, with a total mass of 85 kg, emerge from adownhill track onto a horizontal straight track with an initial s

peedof 37 m/s. if a force slows them to a stop at a constant rate of 2.0m/s2, (a) what magnitude f is required for the force, (b) what distanced do they travel while slowing, and (c) what work w is doneon them by the force? what are (d) f, (e) d, and (f) w if they, instead,slow at 4.0 m/s2?

1 answer:

Verdich [7]2 years ago

7 0

<span>(1) </span>Through the Second Law of motion, the equation for Force is:

F = m x a

Where m is mass and a is acceleration (deceleration)

<span>(2) </span>Distance is calculated through the equation,

D = Vi^2 / 2a

Where Vi is initial velocity

<span>(3) </span>Work is calculated through the equation,

W = F x D

Substituting the known values,

Part A:

<span>(1) </span> F = (85 kg)(2 m/s^2) = 170 N

<span>(2) </span> D = (37 m/s)^2 / (2)(2 m/s^2) = 9.25 m

<span>(3) </span> W = (170 N)(9.25 m) = 1572.5 J

Part B:

<span>(1) </span> F = (85 kg)(4 m/s^2) = 340 N

<span>(2) </span>D = (37 m/s)^2 / (2)(4 m/s^2) = 4.625 m

<span>(3) </span><span> W = (340 N)(4.625 m) = 1572.5 J</span>

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