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yKpoI14uk [10]
4 years ago
15

Copper (ii) bromide and lead (ii) acetate express your answer as a chemical equation. identify all of the phases in your answer.

enter noreaction if no no reaction occurs.
Chemistry
2 answers:
Artist 52 [7]4 years ago
6 0

Explanation:

Aqueous solution of copper (II) bromide when reacts with aqueous solution of lead (II) acetate then it results in the formation of an insoluble solid of lead bromide and an aqueous solution of copper acetate.

The chemical reaction equation will be as follows.

       Pb(CH_{3}COO)_{2}(aq) + CuBr_{2}(aq) \rightarrow Cu(CH_{3}COO)_{2}(aq) + PbBr_{2}(s)

This reaction is basically a double displacement reaction.

Andrews [41]4 years ago
3 0
CuBr2(aq)+CH3COOPb(aq)
----->PbBr2(s)+CH3COOCu(aq)
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Elements donate 2 electron to produce a cation with a 2+ charge
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Answer: alkaline earth metals (group-IIA)

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The element which donates the electron is known as electropositive element and forms a positively charged ion called as cation. The element which accepts the electrons is known as electronegative element and forms a negatively charged ion called as anion.

Alkaline earth metals donate 2 valence electrons to acquire noble gas configuration.

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