Copper (ii) bromide and lead (ii) acetate express your answer as a chemical equation. identify all of the phases in your answer.
2 answers:
Explanation:
Aqueous solution of copper (II) bromide when reacts with aqueous solution of lead (II) acetate then it results in the formation of an insoluble solid of lead bromide and an aqueous solution of copper acetate.
The chemical reaction equation will be as follows.
This reaction is basically a double displacement reaction.
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When the enthalpy value is given, we can calculate how much heat is use or produces in a given equation.
67.6 kCal ---> 67.6 kCal= 1 mol of reaction
1 mol of reaction= 1 mol of CO (based on the coefficient)
so 1 mole of CO gives us 67.6 kCal of heat.
calculation:
1 mol CO
67.6 kCal ---> 67.6 kCal= 1 mol of reaction
1 mol of reaction= 1 mol of CO (based on the coefficient)
so 1 mole of CO gives us 67.6 kCal of heat.
calculation:
1 mol CO