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yKpoI14uk [10]
4 years ago
15

Copper (ii) bromide and lead (ii) acetate express your answer as a chemical equation. identify all of the phases in your answer.

enter noreaction if no no reaction occurs.
Chemistry
2 answers:
Artist 52 [7]4 years ago
6 0

Explanation:

Aqueous solution of copper (II) bromide when reacts with aqueous solution of lead (II) acetate then it results in the formation of an insoluble solid of lead bromide and an aqueous solution of copper acetate.

The chemical reaction equation will be as follows.

       Pb(CH_{3}COO)_{2}(aq) + CuBr_{2}(aq) \rightarrow Cu(CH_{3}COO)_{2}(aq) + PbBr_{2}(s)

This reaction is basically a double displacement reaction.

Andrews [41]4 years ago
3 0
CuBr2(aq)+CH3COOPb(aq)
----->PbBr2(s)+CH3COOCu(aq)
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What volume of a concentrated HCl solution, which is 36.0% HCl by mass and has a density of 1.179 g/mL, should be used to make 4
Ivenika [448]

Answer:

130ml of HCl(36%) in 4.90L solution => pH = 1.50

Explanation:

Need 4.90L of HCl(aq) solution with pH = 1.5.

Given pH = 1.5 => [H⁺] = 10⁻¹·⁵M = 0.032M in H⁺

[HCl(36%)] ≅ 12M in HCl

(M·V)concentrate = (M·V)diluted

12M·V(conc) = 0.032M·4.91L

=> V(conc) needed = [(0.032)(4.91)/12]Liters = 0.0130Liters or 130 ml.

Mixing Caution => Add 131 ml of HCl(36%) into a small quantity of water (~500ml) then dilute to the mark.

5 0
3 years ago
Name two uses for seismometers
NNADVOKAT [17]
Earthquakes and volcanic eruption
8 0
3 years ago
Angiosperms produce brightly colored blooms and sweet-smelling flowers. Why have angiosperms developed these adaptations? A. to
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C

Explanation:

Angiosperms have developed these adaptations because it attracts pollinators which helps the ecosystem grow.

3 0
3 years ago
In Universe , recently discovered by an intrepid team of chemists who also happen to have studied interdimensional travel, quant
tiny-mole [99]

Answer:

Check the explanation

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When talking about our universe there are 5 d orbitals. The element of first transition series moves away from the universal principles of Hund's rule and Aufbav's principle. So in order to attain stability these elements tend to form half or full filled orbitals.

In our universe the ground state electronic configuration of sixth transition metal, Iron (Fe) :  [Ar] 3d^{6} 4s^{2}

and the electronic configuration of seventh transition metal, Cobalt (Co) :  [Ar] 3d^{7} 4s^{2}

=================================

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In universe L there are seven orbitals.

Ground state electronic configuration of sixth and seven transition element.

Sixth transition metal: [Ar] 3d^{7} 4s^1 or [X] 3d^{7} 4s^1

Seventh transition metal: [Ar] 3d^{7} 4s^{2}or [X] 3d^{7} 4s^{2}

7 0
3 years ago
onsider the reaction, NO2(g) + CO(g) → NO(g) + CO2(g), for which the rate law has been determined to be: Rate = k[NO2]2[CO]. Whi
nlexa [21]

Answer:

The correct answer is option D.

Explanation:

Rate of the reaction is a change in the concentration of any one of the reactant or product per unit time.

NO_2(g) + CO(g)\rightarrow NO(g) + CO_2(g)

Rate of the reaction:

R=-\frac{1}{1}\times \frac{d[NO_2]}{dt}=-\frac{1}{1}\times \frac{d[CO]}{dt}

Rate of decrease in nitrogen dioxide concentration is equal to the rate of decrease in carbon monoxide.

Given rate expression of the reaction:

R = k[NO2]^2[CO]

Rate of the reaction on doubling concentration of nitrogen dioxide and carbon monoxide : R'

R'=k(2\times [NO_2])^2(2\times [CO])=8\times k[NO2]^2[CO]=8R

Doubling the concentrations of nitrogen dioxide and carbon monoxide simultaneously will increase the rate of the reaction by a factor of eight.

Hence, none of the given statements are true.

6 0
3 years ago
Read 2 more answers
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