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vlada-n [284]
4 years ago
11

When aluminum is placed in concentrated hydrochloric acid hydrogen gas is produced. what mass?

Chemistry
1 answer:
Natali5045456 [20]4 years ago
4 0
I cannot answer this question if no initial mass for aluminum is given. Le'ts just suppose the initial mass of aluminum is 5 g. The reaction would be:

2 Al + 6 HCl --> 3 H₂ + 2 AlCl₃

The stoichiometric calculations are as follows:

Mass H₂ = 5 g Al * 1 mol/27 g Al * 3 mol H₂/2 mol Al * 2 g H₂/mol = <em>0.556 g H₂ produced</em>
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Element X is in group 2, and element Y is in group 7, of the periodic table. which ions will be present in the compound formed w
12345 [234]

Answer:

Element X has valency 2 while Y Valency 2, element Y has high tendency of gaining electrons for its stability thus the compound formed will be B

elements X is positively charged while Y will be negatively charged

8 0
3 years ago
A sample of sulfurous acid (H2SO3) has a mass of 1.31 g.
lakkis [162]

Answer:

a) 2 (H+) ions

b) 1 (SO3²-) ions

c) 1.36 × 10^-22 grams.

Explanation:

According to this question, sulfurous acid has a chemical formula; H2SO3. It is made up of hydrogen and sulfite ion. Hydrogen ion (H+) is the cation while sulfite ion (SO32-) is the anion.

Based on the chemical formula, there are 2 moles of hydrogen ions that reacts with 1 mole of sulfite ion as follows:

2H+ + SO3²- → H2SO3

Hence;

- there are 2 hydrogen ions (2H+) present in H2SO3.

- there is 1 sulfite ion (SO3²-) present in H2SO3.

c) The mass of one formula unit of H2SO3 is calculated thus:

= 1.008 (2) + 32.065 + 15.999(3)

= 2.016 + 32.065 + 47.997

= 82.08 a.m.u

Since, 1 gram is = 6.02 x 10^23 a.m.u

82.08 a.m.u = 82.08/6.02 × 10^-23

= 13.6 × 10^-23

= 1.36 × 10^-22 grams.

6 0
3 years ago
How many grams of Ni are formed from 55.3 g of Ni2O3?<br><br> 2Ni2O3(s)⟶4Ni(s)+3O2(g)
Neko [114]

Answer:

39.2 g

Explanation:

  • 2Ni₂O₃(s) ⟶ 4Ni(s) + 3O₂(g)

First we <u>convert 55.3 grams of Ni₂O₃ into moles of Ni₂O₃</u>, using its<em> molar mass</em>:

  • 55.3 g ÷ 165.39 g/mol = 0.334 mol Ni₂O₃

Then we <u>convert 0.334 moles of Ni₂O₃ into moles of Ni</u>, using the <em>stoichiometric coefficients of the balanced reaction</em>:

  • 0.334 mol Ni₂O₃ * \frac{4molNi}{2molNi_2O_3} = 0.668 mol Ni

Finally we <u>calculate how much do 0.668 Ni moles weigh</u>, using the<em> molar mass of Ni </em>:

  • 0.668 mol Ni * 58.69 g/mol = 39.2 g
7 0
3 years ago
What process occurs during the corrosion of iron?
Butoxors [25]

Answer:

A

Explanation:

The iron corrodes so it oxidized

8 0
3 years ago
The graph below shows how the amount of carbon dioxide (CO2) in our atmosphere has changed since 1960. A graph that plots the am
fenix001 [56]

Answer:

greenhouse effect

Explanation:

8 0
4 years ago
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