Answer : The partial pressure of
is, 222.93 torr
Explanation :
Half-life = 2.81 hr = 168.6 min
First we have to calculate the rate constant, we use the formula :



Now we have to calculate the partial pressure of 
The balanced chemical reaction is:

Initial pressure 760 0 0
At eqm. (760-2x) 4x x
Expression for rate law for first order kinetics is given by:

where,
k = rate constant
t = time passed by the sample = 215 min
a = initial pressure of
= 760 torr
a - x = pressure of
at equilibrium = (760-2x) torr
Now put all the given values in above equation, we get:


The partial pressure of
= x = 222.93 torr
Reason 1: Allows us to handle larger numbers with ease
Reason 2: Allows us to easily tell the number of significant figures with ease.
Answer: 2.52 M
Explanation:
The product of molarity (moles/litre) and volume in litres yields moles, and the numbers of moles in two solutions means dilute and concentrated are equal, which is expressed by the following equation:


Answer:
Non-zero digits are always significant.
Any zeros between two significant digits are significant.
A final zero or trailing zeros in the decimal portion ONLY are significant. If a number ends in zeros to the right of the decimal point, those zeros are significant.
Explanation:
1.138 has 4 significant figures, which are 1, 1, 3 and 8. The numbers after the decimal point are decimals and are significant figures.
<span>Mixing magnesium and aluminum together produces an excellent lightweight material from which to make airplane parts. This type of mixture is called an alloy.
Alloy is a mixture of two elements, one of which is a metal.
</span>