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Mazyrski [523]
4 years ago
11

Two closed systems A (4000 kJ of thermal energy at 30°C) and B (3000 kJ of thermal energy at 40°C) are brought into contact with

each other. Determine the direction of any heat transfer between the two systems and explain why.
Engineering
1 answer:
torisob [31]4 years ago
5 0

Answer:

The direction of any heat transfer between the systems will be from system B to System A.

Explanation:

The direction of any heat transfer between the systems will be from system B to System A.

Even if the system A has a higher thermal Energy it will be from B to A because the system B has a higher temperature than A. The energy will be transferred from B to A until the temperature of the two systems equals and the temperature is in equilibrium.

This comes from the fundamental law of thermodynamics.

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Which of the following describes how the author introduces dust storms in the text??​
Oduvanchick [21]

Answer:

B-as deadly storms that claim lives in th great pines

Explanation:

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8 0
3 years ago
Read 2 more answers
A sample of wastewater is diluted 10 times. The diluted solution has an ultimate biochemical oxygen demand (BOD), Lo, of 30 mg/L
zzz [600]

Answer:

474.59 mg/L

Explanation:

Given that

BOD = 30 mg/L

Original BOD  = 30 mg/L × dilution factor

Original BOD  = 30 mg/L  × 10 = 300 mg/L

L_o = \frac{BOD}{1-e^{-5t}}

here L_o is the ultimate BOD ; BOD is the  biochemical oxygen demand ;  t = 0.20 /day

L_o = \frac{300}{1-e^{-5(0.20)}}

L_o = 474.59 \ mg/L

3 0
4 years ago
Air initially at 15 psla and 60 F is compressed to 75 psia and 400 F. The power input to air under steady state condition is 5 h
Triss [41]

Answer:\dot{m}=3.46lbm/min

Explanation:

Initial conditions

P_1=15 psia

T_1=60 F^{\circ}

Final conditions

P_2=75 psia

T_2=400F^{\circ}

Steady flow energy equation

\dot{m}\left [ h_1+\frac{v_1^2}{2}+gz_1\right ]+\dot{Q}=\dot{m}\left [ h_2+[tex]\frac{v_2^2}{2}+gz_2\right ]+\dot{W}

\dot{m}\left [ c_pT_1+\frac{0^2}{2}+g0\right ]+\dot{Q}=\dot{m}\left [ c_pT_2+\frac{0^2}{2}+g0\right ]+\dot{W}

\dot{m}c_p\left [ T_1-T_2\right ]+\left [ -5hp\right ]=\dot{W} -5\times 746\times 3.4121

-4\dot{m}-\dot{m}\times 0.24\times \left [ 400-60\right ]

-81.6\dot{m}-4\dot{m}=-4.949 BTU/sec

\dot{m}=0.057821lbm/sec

\dot{m}=3.46lbm/min

3 0
3 years ago
A divided multilane highway in a recreational area has four lanes (two lanes in each direction) and is on rolling terrain. The h
sertanlavr [38]

Answer:

Explanation:

Before: PT= 0.10, PB= 0.03 (given) ET = 2.5 ER = 2.0 (Table 6.5)

fHV= 0.847 (Eq. 6.5) PHF = 0.95, fp= 0.90, N=2, V = 2200 (given)

vp= V/[PHF⋅fHVTB⋅fp⋅N] = 1518.9 (Eq. 6.3)

BFFS = 50+5, BFFS =55 (given) fLW= 6.6

TLC=6+3=9 fLC= 0.65

fM= 0.0

fA= 1.0

FFS = BFFS −fLW−fLC–fM–fA= 46.75 (Eq. 6.7)

Use FFS=45 D= vp/S = 33.75pc/mi/ln Eq (6.6)

After: fA= 3.0

FFS = BFFS −fLW−fLC–fM–fA= 44.75 (Eq. 6.7)

Use FFS=45 Vnew= 2600 Vp= Va/[PHF⋅fHB⋅fp⋅N] = 1795 (Eq. 6.3) D= vp/S = 39.89pc/mi/ln

8 0
3 years ago
4.A compression spring has a diameter of 0.67 in and a coil diameter of 0.067 in, with 30 total coils. The spring is to be made
Akimi4 [234]

Answer:

Fatigue factor of safety is 2.0267

Explanation:

Solution is attached below.

4 0
4 years ago
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