All categories

3 years ago

Helpppp mee

2 answers:

7 0

Distance is the total length of the follwed by a movig partical.
Velocity is the rate of change of distance with respect to time. acceleration is the rate of change of velocity with respect to time.

RideAnS [48]3 years ago

6 0

Distance is measurable velocity is the speed of something and acceleration is the capacity to gain speed within a short amout of time
EXAMPLES
distance how far utah is from california
velocity the time it take you to run home
acceleration is like how soon a car reaches 25 mph

You might be interested in

Calculate the final temperature of a mixture of 0.350 kg of ice initially at 218°C and 237 g of water initially at 100.0°C.

kramer

Answer:

115 ⁰C

Explanation:

Step 1: The heat needed to melt the solid at its melting point will come from the warmer water sample. This implies

$q_{1} +q_{2} =-q_{3}$ -----eqution 1

where,

$q_{1}$ is the heat absorbed by the solid at 0⁰C

$q_{2}$ is the heat absorbed by the liquid at 0⁰C

$q_{3}$ the heat lost by the warmer water sample

Important equations to be used in solving this problem

$q=m *c*\delta {T}$ , where -----equation 2

q is heat absorbed/lost

m is mass of the sample

c is specific heat of water, = 4.18 J/0⁰C

$\delta {T}$ is change in temperature

Again,

$q=n*\delta {_f_u_s}$ -------equation 3

where,

q is heat absorbed

n is the number of moles of water

tex]\delta {_f_u_s}[/tex] is the molar heat of fusion of water, = 6.01 kJ/mol

Step 2: calculate how many moles of water you have in the 100.0-g sample

$=237g *\frac{1 mole H_{2} O}{18g} = 13.167 moles of H_{2}O$

Step 3: calculate how much heat is needed to allow the sample to go from solid at 218⁰C to liquid at 0⁰C

$q_{1} = 13.167 moles *6.01\frac{KJ}{mole} = 79.13KJ$

This means that equation (1) becomes

79.13 KJ + $q_{2} = -q_{3}$

Step 4: calculate the final temperature of the water

$79.13KJ+M_{sample} *C*\delta {T_{sample}} =-M_{water} *C*\delta {T_{water}$

Substitute in the values; we will have,

$79.13KJ + 237*4.18\frac{J}{g^{o}C}*(T_{f}-218}) = -350*4.18\frac{J}{g^{o}C}*(T_{f}-100})$

79.13 kJ + 990.66J* $(T_{f}-218})$ = -1463J* $(T_{f}-100})$

Convert the joules to kilo-joules to get

79.13 kJ + 0.99066KJ* $(T_{f}-218})$ = -1.463KJ* $(T_{f}-100})$

$79.13 + 0.99066T_{f} -215.96388= -1.463T_{f}+146.3$

collect like terms,

2.45366 $T_{f}$ = 283.133

∴ $T_{f} =$ = 115.4 ⁰C

Approximately the final temperature of the mixture is 115 ⁰C

6 0

3 years ago

An object has an acceleration of 6.0 m/s/s. if the net force acting upon this object were doubled, then its new acceleration wou

Flauer [41]

F has direct relation with a
then doubling F cause acc. to get double i:e 6×2=12

5 0

3 years ago

Question 2 10

ss7ja [257]

B Ik it all just know who they’ll you

8 0

3 years ago

What is scientific learning

bixtya [17]

Hello here

It means that a person has the ability to describe, explain, and predict natural phenomena.

4 0

2 years ago

Please answer this question brainliest ko promise

Paul [167]

Answer:

The language you typed into the bar is Filipinio and can be translated to "what sources of information do you have in your home and how can it help?"

The sources of information most people have in their home are Books, Encyclopedias, Magazines, Databases, Newspapers, Library Catalog, Internet. Hope this helped!

7 0

3 years ago