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S_A_V [24]
3 years ago
5

Helpppp mee

Physics
2 answers:
USPshnik [31]3 years ago
7 0
Distance is the total length of the follwed by a movig partical.
Velocity is the rate of change of distance with respect to time.  acceleration is the rate of change of velocity with respect to time. 
RideAnS [48]3 years ago
6 0
Distance is measurable velocity is the speed of something and acceleration is the capacity to gain speed within a short amout of time 
EXAMPLES
distance how far utah is from california
velocity the time it take you to run home 
acceleration is like how soon a car reaches 25 mph

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Based on Archimedes' principle, the greatest buoyant force an object can experience in water is determined by which quantity?
ValentinkaMS [17]

Answer:

B. The object's volume

Explanation:

When an object is immersed in a fluid, it experiences an upward force which is called buoyant force. The magnitude of the buoyant force is given by:

B=\rho_f V_{disp} g

where

\rho_f is the density of the fluid in which the object is immersed

V_{disp} is the volume of the fluid displaced by the object

g is the acceleration due to gravity

When the object is totally immersed in the fluid, V_{disp} corresponds to the volume of the object; when the object is only partially immersed, V_{disp} corresponds only to the volume of the part of the object immersed.

From the formula, we see that the greatest buoyant force is experienced by the object when it is fully immersed. Moreover, we see that the buoyant force depends only on one property of the object: its volume. Therefore, the correct choice is

B. The object's volume

6 0
4 years ago
A car has a uniform velocity of 108km/h. How far does it travel in 30 seconds?​
natita [175]
  • Velocity=108km/h

Convert to m/s

\\ \tt\longmapsto 108\times \dfrac{5}{18}

\\ \tt\longmapsto 30m/s

  • Time=30s.

\\ \tt\longmapsto Distance=Velocity\times Time

\\ \tt\longmapsto Distance=30(30)

\\ \tt\longmapsto Distance=900m

6 0
3 years ago
If force remains constant and acceleration decreases what must happen to the mass
blondinia [14]

That can only be happening if the mass mysteriously increased somehow.  I'd like to know how in the world THAT happened.

4 0
3 years ago
A 2.3 m long wire weighing 0.075 N/m is suspended directly above an infinitely straight wire. The top wire carries a current of
ZanzabumX [31]

Answer:

Explanation:

Magnetic field near current carrying wire

= \frac{\mu_0}{4\pi} \frac{2i}{r}

i is current , r is distance from wire

B =  10⁻⁷ x \frac{2\times49}{r}

force on second wire per unit length

B I L , I is current in second wire , L is length of wire

=  10⁻⁷ x \frac{2\times49}{r} x 33 x 1

= 3234 x \frac{10^{-7}}{r}

This should balance weight of second wire per unit length

3234 x \frac{10^{-7}}{r} = .075

r = \frac{3234}{.075} x 10⁻⁷

= .0043 m

= .43 cm .

5 0
3 years ago
The equation of a transverse wave traveling along a very long string is y 6.0 sin(0.020px 4.0pt), where x and y are expressed in
zhannawk [14.2K]

Answer:

given

y=6.0sin(0.020px + 4.0pt)

the general wave equation moving in the positive directionis

y(x,t) = ymsin(kx -?t)

a) the amplitude is

ym = 6.0cm

b)

we have the angular wave number as

k = 2p /?

or

? = 2p / 0.020p

=1.0*102cm

c)

the frequency is

f = ?/2p

= 4p/2p

= 2.0 Hz

d)

the wave speed is

v = f?

= (100cm)(2.0Hz)

= 2.0*102cm/s

e)

since the trignometric function is (kx -?t) , sothe wave propagates in th -x direction

f)

the maximum transverse speed is

umax =2pfym

= 2p(2.0Hz)(6.0cm)

= 75cm/s

g)

we have

y(3.5cm ,0.26s) = 6.0cmsin[0.020p(3.5) +4.0p(0.26)]

= -2.0cm

6 0
3 years ago
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