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S_A_V [24]
3 years ago
5

Helpppp mee

Physics
2 answers:
USPshnik [31]3 years ago
7 0
Distance is the total length of the follwed by a movig partical.
Velocity is the rate of change of distance with respect to time.  acceleration is the rate of change of velocity with respect to time. 
RideAnS [48]3 years ago
6 0
Distance is measurable velocity is the speed of something and acceleration is the capacity to gain speed within a short amout of time 
EXAMPLES
distance how far utah is from california
velocity the time it take you to run home 
acceleration is like how soon a car reaches 25 mph

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The weight could be different, metals have a higher mass than nonmetals, so when occupying the same amount of space, the weight of the metal is far more.
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Why do we see the sun before it actually rises in the morning?
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<span>Answer: Burrhus Frederic Skinner's Operant Conditioning.

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3 years ago
Two identical charges,2.0m apart,exert forces of magnitude 4.0 N on each other.What is the value of either charge?
storchak [24]

Answer:

\large \boxed{42\, \mu \text{C}}$

Explanation:

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The charges are identical, so we can write the formula as

F=k\dfrac{q^{2}}{r^2}

\begin{array}{rcl}\text{4.0 N}& = & 8.988 \times 10^{9}\text{ N$\cdot$m$^{2}$C$^{-2}$} \times \dfrac{q^{2}}{\text{(2.0 m)}^{2}}\\\\4.0 & = & 2.25 \times 10^{9}\text{ C$^{-2}$} \times q^{2}\\\\q^{2} & = & \dfrac{4.0}{2.25 \times 10^{9}\text{ C$^{-2}$}}\\\\& = & 1.78 \times 10^{-9} \text{ C}^{2}\\q & = & 4.2 \times 10^{-5} \text{ C}\\& = & 42\, \mu \text{C}\\\end{array}\\\text{Each charge has a value of $\large \boxed{\mathbf{42\, \mu }\textbf{C}}$}

7 0
3 years ago
You are given two unknown point charges, Q1, and Q2. At a point on the line joining them, one third of the way from Q1 to Q2 the
podryga [215]
The formula that is applicable here is E = kQ/r^2 in which the energy of attraction is proportional to the charges and inversely proportional to the square of the distance. In this case, 
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3 years ago
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