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Yakvenalex [24]
4 years ago
15

Which of the following would be considered important in including in the summary of an experimental investigation?

Chemistry
2 answers:
just olya [345]4 years ago
7 0

Answer is: variables that were manipulated during the experiment.

The two main variables in an experiment are the independent and dependent variable.

Dependent variable is the variable being tested and measured in a scientific experiment.

Dependent variables depend on the values of independent variables. The dependent variables represent the output or outcome whose variation is being studied.

Laboratory room number is the least important.

saveliy_v [14]4 years ago
5 0

NOOOO GUYS ITS VARIABLES THAT WERE MANIPULATED DURING THE EXPERIMENT i took the test i do homeschool k12

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Answer:

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Explanation:

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3 years ago
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Which reason best explains why metals are ductile instead of brittle?
MaRussiya [10]

Answer: -

Metals are ductile instead of brittle because they have flexible bonds.

Explanation: -

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Metals due to greater bond flexibility are more ductile.

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3 years ago
What is meant by the statement "energy is quantized"?
Sveta_85 [38]

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5 0
3 years ago
Starting from a 1 M stock of NaCl, how will you make 50 ml of 0.15 M NaCl?
WARRIOR [948]

Answer:

We need 7.5 mL of the 1M stock of NaCl

Explanation:

Data given:

Stock = 1M this means 1 mol/ L

A 0.15 M solution of 50 mL has 0.0075 moles NaCl per 50 mL

Step 2: Calculate the volume of stock we need

The moles of solute will be constant

and n = M*V  

M1*V1 = M2*V2

⇒ with M1 = the initial molair concentration = 1M

⇒ with V1 = the volume we need of the stock

⇒ with V2 = the volume we want to make of the new solution = 50 mL = 0.05 L

⇒ with M2 = the concentration of the new solution = 0.15 M

1*V1 = 0.15*(50)

V1 = 7.5 mL

Since 0.0075 L of 1M solution contains 0.0075 moles

50 mL solution will contain also 0.0075 moles but will have a molair concentration of 0.0075 moles / 0.05 L =0.15 M

We need 7.5 mL of the 1M stock of NaCl

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