Answer:
30.3 g
Explanation:
At STP, 1 mol of any gas will occupy 22.4 L.
With the information above in mind, we <u>calculate how many moles are there in 32.0 L</u>:
- 32.0 L ÷ 22.4 L/mol = 1.43 mol
Then we <u>calculate how many moles would there be in 16.6 L</u>:
- 16.6 L ÷ 22.4 L/mol = 0.741 mol
The <u>difference in moles is</u>:
- 1.43 mol - 0.741 mol = 0.689 mol
Finally we <u>convert 0.689 moles of CO₂ into grams</u>, using its <em>molar mass</em>:
- 0.689 mol * 44 g/mol = 30.3 g
Meiosis 1 is the reductional division ! so after telophase 1 , cytokinesis takes place and two haploid cells are formed !
Answer:
Depending on the deformity it will depend on the amount of the ice that is melted,it the majority is melted that is relevant to the heated liquid melting the ice,so yes only the water formalities of the melted ice.
Answer:
15.6g Ag2SO4
Explanation:
2AgNO3 + H2SO4 --> Ag2SO4 + 2HNO3
-2x -x
0.1-2x. 0.155-x
x=0.05 x=0.155
0.05mol Ag2SO4 x 311.78g = 15.6g Ag2SO4
