The concentration of the chemist's working solution is 6.718 mol/L.
Given,
The volume of silver perchlorate solution (V₁) = 790 ml.
The volume of distilled water added to the silver perchlorate(V₂) = 290ml.
The concentration of a stock solution of silver perchlorate (C₂) = 18.3 mol/L.
We have to find the concentration of the chemist's working solution (C₁).
As we know,
V₁C₁ = V₂C₂
From the above formula, we get,
C₁ = V₂C₂/V₁
C₁ = 290 × 18.3/ 790
C₁ = 6.718 mol/L
The concentration of the working solution = 6.718 mol/L
Hence, the concentration of the chemist's working solution is 6.718 mol/L.
To learn more about the concentration or stock's solution, visit: brainly.com/question/14510306
#SPJ4
Answer:
Density = mass/volume
= 44/22.4
= 1.96 gram/liter
The density of the Carbon Dioxide at S.T.P. (Standard Temperature and Volume) is 1.96 gram/liter.
Answer:
Work done, W = 100 J
Explanation:
We have, Billy the friendly Robot uses 50 N of force to lift a box 2 meters in the air.
It is required to find the work done by Billy.
Work done by an object is given in terms of force and displacement. The formula used to find the work done is given by :

So, the work performed by Billy is 100 J.
Answer:
conditioning-the process of associating a stimulus with a good or bad outcome.
trial-and-error learning-the process of performing a behavior more and more skillfully.
insight learning-the process of using prior knowledge to solve a problem.
imprinting-a bond to an indivisual or object shortly after birth or hatching.
Explanation:
Did this assignment.