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LiRa [457]
3 years ago
12

A bullet is shot from a rifle with a speed of 720 m/s. What time is required for the bullet to strike a target 3240 meters away

?
Physics
2 answers:
Alik [6]3 years ago
7 0
4.5 seconds you devoured 3240/720=4.5
Nataliya [291]3 years ago
4 0

Answer:

Time taken, t = 4.5 seconds

Explanation:

Speed of the bullet, v = 720 m/s

Distance to be covered by the target, d = 3240 m

Let t is the time required for the bullet to strike a target. The time taken is calculated as :

t=\dfrac{d}{v}

t=\dfrac{3240\ m}{720\ m/s}

t = 4.5 seconds

So, the time required for the bullet to strike a target is 4.5 seconds. Hence, this is the required solution.

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                                                      H_{1}^{1}+H_{1} ^{1} =H_{1} ^{2} +e_{+1} ^{0} +energy

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                                                      He_{2} ^{3}+H_{1} ^{1} =He_{2} ^{4} +e_{+1} ^{0} +energy

                                                       -----------------------------------------------------------------------

                                                        4H_{1} ^{1} = He_{2} ^{4} +2e_{+1} ^{0} +energy

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6 0
3 years ago
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the process of making alloys involves _____ pure metals to remove impurities. Then the pure metals are ____ with other component
Law Incorporation [45]
I think this is the answer for the first line(Cooling ,Heating or mixing ) and for the second line is(broken down,cooled,mixed)
5 0
3 years ago
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The battleship and enemy ships 1 and 2 lie along a straight line. Neglect air friction. battleship 1 2 Consider the motion of th
DaniilM [7]

Answer:

\frac{t_1}{t_2} = \frac{sin\theta_1}{sin\theta_2}

Explanation:

The vertical component of the initial velocities are

v_v = v_0sin\theta

If we ignore air resistance, and let g = -9.81 m/s2. The the time it takes for the projectiles to travel, vertically speaking, can be calculated in the following motion equation

v_vt - gt^2/2 = s = 0

t(v_v - gt/2) = 0

v_v - gt/2 = 0

t = 2v_v/g = 2v_0sin\theta/g

So the ratio of the times of the flights is

t_1 / t_2 = \frac{2v_0sin\theta_1/g}{2v_0sin\theta_2/g} = \frac{sin\theta_1}{sin\theta_2}

8 0
3 years ago
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