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LiRa [457]
2 years ago
12

A bullet is shot from a rifle with a speed of 720 m/s. What time is required for the bullet to strike a target 3240 meters away

?
Physics
2 answers:
Alik [6]2 years ago
7 0
4.5 seconds you devoured 3240/720=4.5
Nataliya [291]2 years ago
4 0

Answer:

Time taken, t = 4.5 seconds

Explanation:

Speed of the bullet, v = 720 m/s

Distance to be covered by the target, d = 3240 m

Let t is the time required for the bullet to strike a target. The time taken is calculated as :

t=\dfrac{d}{v}

t=\dfrac{3240\ m}{720\ m/s}

t = 4.5 seconds

So, the time required for the bullet to strike a target is 4.5 seconds. Hence, this is the required solution.

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A 0.35 m2 coil with 50 turns rotates at 5 radians per sec2 in a magnetic field of 0.6 Tesla. What is the value of the rms curren
soldier1979 [14.2K]

Answer:

11.25 amps

Explanation:

For transformers, the magnetic flux

\Phi _{max} = \beta  \times A

Therefore;

\Phi _{max} = 0.6  \times 0.35 = 0.21 \ Weber

Ф = Фmax (cosωt) = 0.21·(cos(5·t))

From Faraday's law of induction, we have;

ε = -N × dΦ/dt

Which gives;

dΦ/dt = -1.05(sin (5t) )

ε = -N × dΦ/dt = -50× -1.05(sin (5t) )

ε = 52.5(sin (5t) )

I = ε/R = 52.5(sin (5t) )/3.3 = 15.9091(sin (5t) ) amps

The peak current is therefore = 15.9091 amps

The rms current = Peak current /√2 = 15.9091/(√2) = 11.25 amps.

5 0
3 years ago
Help, It has multiple answers for this question.
evablogger [386]
The answer is ultra violet radiation. From the air
4 0
3 years ago
Which uses motion of water in nature to produce electricity?
Zinaida [17]

Answer: D. Hydroelectric power

Explanation: Hydroelectric means water power (not exactly but "hydro" is water and electric is well self explanatory)

6 0
3 years ago
Which best describes fusion nuclear reactors? They use rods containing uranium for fuel. They are currently used for electricity
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They has been very successful but they are very expensive to operate that is your answer I hope this helps
6 0
3 years ago
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A 500 kg sack of coal falls vertically onto a 2000 kg railroad flatcar which was initially moving horizontally at 3 m/s. no exte
Zinaida [17]

Since there are no external forces, including friction, act on the flatcar. after the sack rests on the flatcar, we would assume that momentum is conserved. This means that

total momentum of car before collision = total momentum of car after collision.

Recall,

momentum = mass x velocity

From the information given,

mass of car before collision = 2000

velocity of car before collision = 3

Thus,

total momentum of car before collision = 2000 x 3 = 6000

Also,

mass of sack = 500

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momentum after collision = 2500 x v = 2500v

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v = 6000/2500

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the speed of the flatcar is 2.4 m/s

6 0
11 months ago
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