A bullet is shot from a rifle with a speed of 720 m/s. What time is required for the bullet to strike a target 3240 meters away
2 answers:
Answer:
Time taken, t = 4.5 seconds
Explanation:
Speed of the bullet, v = 720 m/s
Distance to be covered by the target, d = 3240 m
Let t is the time required for the bullet to strike a target. The time taken is calculated as :
t = 4.5 seconds
So, the time required for the bullet to strike a target is 4.5 seconds. Hence, this is the required solution.
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Given that,
Height =1.5 m
Angle = 45°
We need to find the greater speed of the ball
Using conservation of energy
Here, initial velocity and final potential energy is zero.
Put the value into the formula
Hence, the greater speed of the ball is 5.42 m/s.
From the activity values and the decay constant, the mass of of Strontium in the sample is:
The decay constant of an element is the probability of decay of a nucleus per unit time.
{λ = ln 2 / t1/2
where;
t1/2 is the half-life of the isotope.
The half-life is converted to seconds since the decay constant is asked in per seconds.
Hence;
The activity of the element, A, the decay constant, λ and the number of nuclei, N are related as follows:
- A = (–) λN
Molar mass of Strontium-90 is 90 g.
1 mole of Strontium-90 contains 6.02×10^23 nuclei.
The mass, m of Strontium in the sample is calculated:
Therefore, the mass of of Strontium in the sample is:
Learn more about decay constant at: brainly.com/question/17159453