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Gre4nikov [31]
2 years ago
6

What is the length of a box in which the minimum energy of an electron is 1.5*10^-18 J?

Physics
1 answer:
Sidana [21]2 years ago
8 0

Answer:

L=2*10^-10m

Explanation:

we need to evaluate for a minimum energy:

Planck constant=  h = 6,62607015 ×10 -34 kg⋅m2⋅s−1

1.5*10^-18J = 10eV

En=  n^2h^2 /  8mL^2

for n=1 (minimum energy)

E1=  h^2 /  8mL^2

so...

L^2= h^2/(8mE1)

L^2= (6.63*10^-34)^2 / [ 8(9.11*10^-31 )*(1.5*10^-18J )]

L^2= 4.02*10^-20

L= 2*10^-10 m

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