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sammy [17]
3 years ago
10

King Arthur is riding his horse toward a raised drawbridge of his castle with a velocity of five m/s westward. The drawbridge at

tendant begins to lower the drawbridge which takes 15 seconds to lower. If King Arthur is 80 meters east of the edge of the moat when the drawbridge begins to go down will the drawbridge lower in time for him to cross without stopping?
Physics
2 answers:
Dominik [7]3 years ago
8 0
Yes , the drawbridge will finish lowering 1 second before king arthur arrives 
densk [106]3 years ago
7 0

yes, king Arthur will be 1 second early  for the drawbridge to lower.

the key is to find the time by dividing the distance over the velocity (speed) and you get 16 seconds therefore you have one extra second left

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uniform electric field exists between two parallel plates separated by 2.0 cm. The intensity of the field is 15 kN/C. What is th
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Answer:

potential difference V= 300 volts

Explanation:

Given:

d= 2.0 cm = 0.02m

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For a uniform field between two plates, the Electric Filed Intensity (E) is proportional to the potential difference (V) and inversely  proportional to distance between the plates.

E= V/d

⇒ V= E×d = 15 × 10³ N/C × 0.02 m = 300 volts  (∴1 Nm/C = 1 J/C= 1 volts)

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A circular cross section, d = 25 mm, experiences a torque load, T = 25 N·m, and a shear force, V = 85 kN. Calculate the shear st
Maru [420]

Answer:

The correct answer is 231 Mpa i.e option a.

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I_{p} = polar moment of inertia of the section

r = radial distance from the center

Thus we can see that if a point is located at center i.e r = 0 there will be no shearing stresses at the center due to torque.

We know that in case of a circular section the maximum shearing stresses due to a shear force occurs at the center and equals

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Applying values we get

\tau _{max}=\frac{4}{3}\times \frac{85\times 10^{3}}{0.25\times \pi \times (25\times 10^{-3})^{2}}\\\\\therefore \tau _{max}=230.88Mpa\approx 231Mpa

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Answer:

if not mistaken its b

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