Sin100cos40-cos100sin40

Physics

1 answer:

Andre45 [30]4 years ago

6 0

Answer:

Sin(60°)= $\frac{\sqrt{3} }{2}$

Explanation:

Assuming the given angles are in degrees

We know that Sin(A-B)=SinACosB-CosASinB

Here A=100° and B=40°

$Sin(100)Cos(40)-Cos(100)Sin(40)=Sin(100-40)=Sin(60)=\frac{\sqrt{3} }{2}$

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