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How many moles of hno3 are present if 0.108 mol of ba(oh)2 was needed to neutralize the acid solution? express your answer with

belka [17]

The balanced equation for the neutralisation reaction is as follows
2HNO₃ + Ba(OH)₂ ---> Ba(NO₃)₂ + 2H₂O
stoichiometry of HNO₃ to Ba(OH)₂ is 2:1
number of Ba(OH)₂ mol present - 0.108 mol
1 mol of Ba(OH)₂ neutralises 2 mol of Ba(OH)₂
therefore 0.108 mol of Ba(OH)₂ neutralises - 2 x 0.108 mol = 0.216 mol of HNO₃

6 0

3 years ago

When agno3 was added to test tube d it reacted with cl to form agcl precipitate. Did this result in a shift to the right or the

AlekseyPX

Answer:

Reaction will move rightwards.

Explanation:

Hello there!

In this case, according to the proposed question, it turns out possible for us to figure out the effect of the addition of silver nitrate, by using the following representative equation for the formation of the silver chloride precipitate:

$Ag^+(aq)+Cl^-(aq)\rightleftharpoons AgCl(s)$

Now, due to the addition of silver nitrate, we will be actually adding silver ions to the solution, which means that, in terms of the Le Ch atelier's principle, the reaction will shift to the right towards the formation of more silver chloride precipitate.

Best regards!

4 0

3 years ago

Minerals in geodes form spectacular euhedral crystals because ________. A. all of the elements incorporated in the crystals are

11111nata11111 [884]

Answer:

C. minerals within geodes are always framework silicates

Explanation:

This is true going by the facts that, it is only the silicates that can be able to form crystals as obtainable in diamonds etc. Since the minerals in geodes are in the framework of silicates families, they can be able to form euhedral crystals.

4 0

3 years ago

Find the volume of a rectangular prism that is<br> 25 cm by 10 cm by 15 cm.<br> height<br> length

Stolb23 [73]

Answer:

3750 cm.

Explanation:

You multiply the three side measurements to find the volume.

25cm·10cm·15cm

375cm·10cm

3750 cm.

<em><u>Hope this helps!</u></em>

4 0

3 years ago

Read 2 more answers

How many molecules are in 3.6 grams of NaCl? Question options:

Levart [38]

Answer:

$\boxed {\boxed {\sf 3.7 * 10^{22} \ molecules \ NaCl}}$

Explanation:

We are asked to find how many molecules are in 3.6 grams of sodium chloride.

<h3>1. Convert Grams to Moles </h3>

First, we convert grams to moles using the molar mass. These values are equivalent to atomic masses on the Periodic Table, but the units are grams per moles instead of atomic mass units. Look up the molar masses of the individual elements: sodium and chlorine.

Na: 22.9897693 g/mol
Cl: 35.45 g/mol

There are no subscripts in the chemical formula (NaCl), so we simply add the 2 molar masses.

NaCl: 22.9897693 + 35.45 = 58.4397693 g/mol

Now we will convert using dimensional analysis. First, set up a ratio using the molar mass.

$\frac {58.4397693 \ g \ NaCl}{ 1 \ mol \ NaCl}$

We are converting 3.6 grams to moles, so we must multiply the ratio by this value.

$3.6 \ g \ NaCl *\frac {58.4397693 \ g \ NaCl}{ 1 \ mol \ NaCl}$

Flip the ratio so the units of grams of sodium chloride cancel.

$3.6 \ g \ NaCl *\frac { 1 \ mol \ NaCl}{58.4397693 \ g \ NaCl}$

$3.6 *\frac { 1 \ mol \ NaCl}{58.4397693}$

$\frac { 3.6}{58.4397693} \ mol \ NaCl$

$0.06160188589 \ mol \ NaCl$

<h3>2. Convert Moles to Molecules </h3>

Next, we convert moles to molecules using Avogadro's Number. This is 6.022 × 10²³ and it tells us the number of particles (atoms, molecules, formula units, etc). In this case, the particles are molecules of sodium chloride. Let's set up another ratio.

$\frac {6.022 \times 10^{23} \ molecules \ NaCl}{ 1 \ mol \ NaCl}$

Multiply by the number of moles we calculated.

$0.06160188589 \ mol \ NaCl * \frac{6.022 \times 10^{23} \ molecules \ NaCl}{1 \ mol \ NaCl}$

The units of moles of sodium chloride cancel.

$0.06160188589 * \frac{6.022 \times 10^{23} \ molecules \ NaCl}{1 }$

$3.70966557*10^{22} \ molecules \ NaCl$

<h3>3. Round </h3>

The original measurement of grams (3.6) has 2 significant figures, so our answer must have the same. For the number we found, that is the tenths place. The 0 in the hundredth place tells us to leave the 7 in the tenth place.

$3.7 * 10^{22} \ molecules \ NaCl$

There are $3.7 * 10^{22} \ molecules \ NaCl$ in 3.6 grams and the correct answer is choice D.

5 0

3 years ago