Answer:
it identifies reducing sugars (monosaccharide's and some disaccharides), which have free ketone or aldehyde functional group
Explanation:
It turns from turquoise to yellow or orange when it reacts with reducing sugars.
NaHCO3 = 22.99 + 1.008 + 16(3) = 83.99 g/mol
<span>Na = 22.99g/83.99 g weight of molecule =.2727 or 27.27% </span>
<span>3.0 g* .2727 = 0.8211 grams of sodium in sample of NaHCO3
</span><span>0.8211 grams Na + 1.266 grams Cl = 2.087 grams</span>
Molar mass FeTiO3 => 151.7102 g/mol
atomic mass Ti => 47.867 u
% ( atomic mass Ti / molar mass FeTiO3 ) x 100
= ( 47.867 / 151.7102) x 100
= 0.3155 x 100
= 31.55 % of Ti
hope this helps!
Calcium belongs to the alkaline earth metal group. Within a group, the melting point decreases from top to bottom. This is because the as the atomic radii increases the outer valence electrons are shielded by the inner electrons and experience a lower nuclear attraction. As a result the bonds can be broken easily which lowers their melting point.
The three elements below Calcium ib Group II A which have a lower melting point are: Strontium (Sr), Barium (Ba) and Radium (Ra)
Answer:
[Cl⁻] = 1,5x10⁻⁴M
Explanation:
First of all, let's determinate the mole of each salt.
Molarity . volume = Mole
Volume must be in L, cause molarity is mol/L
NaCl → Na⁺ + Cl⁻
Ratio is 1:1
0.15 mol/L . 0.025L = 3.75x10⁻³ mole
As ratio is 1:1, from 3.75x10⁻³ mole of salt, I have 3.75x10⁻³ mole of chloride
CaCl₂ → Ca²⁺ + 2Cl⁻
Ratio is 1:2 so, from 1 mol of salt I'll get the double of mole of chloride
0.075 mol/L . 0.010 L = 7.5x10⁻⁴ mol
7.5x10⁻⁴ mol . 2 = 1.5x10⁻³ mole
Total mole of Cl⁻: 3.75x10⁻³ + 1.5x10⁻³ = 5.25x10⁻³
This 5.25x10⁻³ mole are present in a total volume of 35 mL.
Let's convert 35 mL in L → 0.035L (35/1000)
Molarity is mol/L → 5.25x10⁻³ mol / 0.035L = 1,5x10⁻⁴M