Can crushers help us recycle in a space efficient way which is good for saving the earth and for giving you more room in your ap
artment. Let us model the illustrated crusher as a planar mechanism that is subjected to the pushing force on the lower "L-shaped" handle, i.e. link CDE. Note that link CDE is one solid piece, pinned at D and E. Knowing that the orange horizontal member has a square peg at that slides vertically in the slot on the blue frame, that the can is centered under the pin at and that N, , , mm, mm, mm, and mm, determine the force magnitude in N exerted on the can from the mechanism. N
1 answer:
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Answer:
I. Tension (cable A) ≈ 6939 lbf
II. Tension (cable B) ≈ 17199 lbf
Explanation:
Let's begin by listing out the data that we were given:
mass of beam (m) = 570 lb, deceleration (cable A) = -20 ft/s², deceleration (cable B) = -2 ft/s²,
g = 32.17405 ft/s²
The tension on an object is given by the product of mass of the object by gravitational force plus/minus the product of mass by acceleration.
Mathematically represented thus:
T = mg + ma
where:
T = tension, m = mass, g = gravitational force,
a = acceleration
I. For Cable A, we have:
T = mg + ma = (570 * 32.17405) + [570 * (-20)]
T = 18339.2085 - 11400 = 6939.2085
T ≈ 6939 lbf
II. For Cable B, we have:
T = mg + ma = (570 * 32.17405) + [570 * (-2)]
T = 18339.2085 - 1140 = 17199.2085
T ≈ 17199 lbf
