Answer:
I think carbon and hydrogen
Sugar and water are made with tiny particles. They are both made from molecules and atoms.
Answer:
The volume is increased.
Explanation:
According to <em>Charles' Law</em>, " <em>at constant pressure the volume and temperature of the gas are directly proportional to each other</em>". Mathematically this law is presented as;
V₁ / T₁ = V₂ / T₂ -----(1)
In statement the data given is,
T₁ = 10 °C = 283.15 K ∴ K = 273.15 + °C
T₂ = 20 °C = 293.15 K
So, it is clear that the temperature is being increased hence, we will find an increase in volume. Let us assume that the starting volume is 100 L, so,
V₁ = 100 L
V₂ = Unknown
Now, we will arrange equation 1 for V₂ as,
V₂ = V₁ × T₂ / T₁
Putting values,
V₂ = 100 L × 293.15 K / 283.15 K
V₂ = 103.52 L
Hence, it is proved that by increasing temperature from 10 °C to 20 °C resulted in the increase of Volume from 100 L to 103.52 L.
Answer:
A 50-mL volumetric cylinder with 0.1-mL accuracy scale should be used for this purpose since three significant figures of accuracy are required.
Explanation:
Hello,
A 50-mL volumetric cylinder with 0.1-mL accuracy scale should be used for this purpose since three significant figures of accuracy are required.
Best regards.
Answer:
The molecular formula of the compound is
. The molecular formula is obtained by the following expression shown below
![\textrm{Molecular formula }= n\times \textrm{Empirical formula}](https://tex.z-dn.net/?f=%5Ctextrm%7BMolecular%20formula%20%7D%3D%20n%5Ctimes%20%5Ctextrm%7BEmpirical%20formula%7D)
Explanation:
Given molecular mass of the compound is 176 g/mol
Given empirical formula is
Atomic mass of carbon, hydrogen and oxygen are 12 u , 1 u and 16 u respectively.
Empirical formula mass of the compound = ![\left ( 2\times12+4+16 \right ) \textrm{ u} = 44 \textrm{ g/mol}](https://tex.z-dn.net/?f=%5Cleft%20%28%202%5Ctimes12%2B4%2B16%20%5Cright%20%29%20%5Ctextrm%7B%20u%7D%20%3D%2044%20%5Ctextrm%7B%20g%2Fmol%7D)
![n = \displaystyle \frac{\textrm{Molecular formula mass}}{\textrm{Empirical formula mass}} \\n = \displaystyle \frac{176}{44} = 4](https://tex.z-dn.net/?f=n%20%3D%20%5Cdisplaystyle%20%5Cfrac%7B%5Ctextrm%7BMolecular%20formula%20mass%7D%7D%7B%5Ctextrm%7BEmpirical%20formula%20mass%7D%7D%20%5C%5Cn%20%3D%20%5Cdisplaystyle%20%5Cfrac%7B176%7D%7B44%7D%20%3D%204)
![\textrm{Molecular formula }= n\times \textrm{Empirical formula}](https://tex.z-dn.net/?f=%5Ctextrm%7BMolecular%20formula%20%7D%3D%20n%5Ctimes%20%5Ctextrm%7BEmpirical%20formula%7D)
Molecular formula = 4
Molecular formula is ![C_{8}H_{16}O_{4}](https://tex.z-dn.net/?f=C_%7B8%7DH_%7B16%7DO_%7B4%7D)