Answer: 306 grams are there in 2.50 moles of potassium chlorate
Explanation
According to avogadro's law, 1 mole of every substance occupies 22.4 L at STP and contains avogadro's number 
of particles.
To calculate the number of moles, we use the equation:
given mass of potassium chlorate = ?
Molar mass of potassium chlorate = 122.55 g/mol
Putting in the values we get:
306 grams are there in 2.50 moles of potassium chlorate
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