Answer:
There are 0.0267 moles of oxygen in 0.658 grams of magnesium nitrate.
Explanation:
Mass of magnesium nitrate = m = 0.658 g
Molar mass of magnesium nitrate = M = 148 g/mol
Moles of magnesium nitrate = n

1 mole of magnesium nitrate has 6 moles of oxygen atoms. Then 0.004446 moles magnesium nitrate will have :

There are 0.0267 moles of oxygen in 0.658 grams of magnesium nitrate.
You would divide 140 (How many electrons) by the numbers of lines.
moles NaOH = 5.20 g * 1 mol / 40.00 g = 0.13 mol
[NaOH] = n/V = 0.13 mol / 0.500L
= 0.26 M
The answer to this question is 0.26 M
A hypothesis is tested by conducting an experiment.
79 and a charge of -2 thx for the points