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Alexxx [7]
3 years ago
14

I ship travels north at 15 km an hour for five hours what is the ships this placement in kilometers

Physics
1 answer:
andrew11 [14]3 years ago
8 0
What you would is is multiply 15km by 5 and end up with 75km
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The capacitor is now disconnected from the battery, and the plates of the capacitor are then slowly pulled apart until the separ
alexdok [17]

Answer:

U₁ = (ϵAV²)/6d

This means that the new energy of the capacitor is (1/3) of the initial energy before the increased separation.

Explanation:

The energy stored in a capacitor is given by (1/2) (CV²)

Energy in the capacitor initially

U = CV²/2

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C = capacitance of the capacitor

But the capacitance of a capacitor depends on the geometry of the capacitor is given by

C = ϵA/d

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So,

U = CV²/2

Substituting for C

U = ϵAV²/2d

Now, for U₁, the new distance between plates, d₁ = 3d

U₁ = ϵAV²/2d₁

U₁ = ϵAV²/(2(3d))

U₁ = (ϵAV²)/6d

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Can someone please help me I don’t understand this
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