<h3>
Answer:</h3>
Element X is Arsenic (Ar)
<h3>
Explanation:</h3>
We are given the compound X₂O₃
The compound is 24.26% Oxygen
We are required to identify element X
<h3>Step 1: Determine the mass of Oxygen in the compound </h3>
Atomic mass of Oxygen is 16.0 g
There are three oxygen atoms in the compound
Therefore;
Mass of oxygen in the compound = 3 × 16
= 48 g
<h3>Step 2: Total mass of the compound </h3>
Total percentage = 100%
But, Oxygen in the compound is 24.26 % and has a mass of 48 g
Therefore;
Mass of the compound = (48 g ÷ 24.26 ) × 100
= 197.857 g
<h3>Step 3 mass of X in the compound </h3>
Since we know the mass of oxygen in the compound and the mass of the compound we can determine the mass of X
Mass of X in the compound = Mass of the compound - Mass of Oxygen in the compound
= 197.857 g - 48 g
= 149.857 g
But there are two atoms of X in the compound.
Therefore, molar mass of X = 149.857 g ÷ 2
= 74.929 g
<h3>Step 4: Identity of element X</h3>
We then we need to identify the element with a molar mass of 74.929 g
Therefore, the element represented above is Arsenic which has an atomic mass of 74.92.
Thus, our compound is Ar₂O₃
