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Bingel [31]
3 years ago
10

Imagine that you are approaching a black hole in a spacecraft. What would you see? What would happen to you?

Physics
2 answers:
aleksandr82 [10.1K]3 years ago
5 0

Answer:

When i look outside the black hole things will look warped.

Explanation:

What I would see depends on the size of the black hole.

If the black hole were small I would die before entering the black hole. I would die even before entering the event horizon. As the tidal forces of a small black are large because of the event horizon being so close to the center of the black hole my body would spaghettifi (being stretched to a small strand like spaghetti) before entering the black hole. The light would bend due to gravitational lensing.

Now, if I were to enter a supermassive black hole then i would be able to enter the event horizon because of its distance from the center of black hole. The light reaching my eyes would bend drastically. The universe outside would look as if it were warped due to gravitational lensing. Then no light would enter my eye as the mass of the black hole consumes me.

HACTEHA [7]3 years ago
3 0
As you approach the event horizon, your body would be pulled towards the black hole. It's a process called sphagettification.

Here's a quote from an article explaining this.
And gravity from the black hole is starting to pull on your feet more than your head. "The gravity wants to sort of stretch you in one direction and squeeze you in another," says Joe Polchinski.<span>
</span>
As for what you see, that is hard to explain without showing a video, at least for me, but you would see this black hole (ha) and whatever is outside starts to flatten and condense (from your POV) then you would fall into the black hole and then it's complete blackness.

But all of this is just educated guessing, and honestly, you'd be dead before anything would happen. 
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Determine the maximum shearing stress in a solid shaft of 1.5-in. diameter as it transmits 75 hp at a speed of 1800 rpm. (Round
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Answer:

\tau=3.96\ ksi

Explanation:

Given that

d= 1.5 in                      ( 1 in = 0.0254 m)

d= 0.0381 m

P= 75 hp                      ( 1 hp = 745.7 W)

P= 55927.5 W

N= 1800 rpm

We know that power P is given as

P=\dfrac{2\pi N\ T}{60}

T=Torque

N=Speed

55927.5=\dfrac{2\times \pi \times 1800\ T}{60}

T=296.85 N.m

The maximum shear stress is given as

\tau=\dfrac{16 T}{\pi d^3}

\tau=\dfrac{16\times 296.85}{\pi \times 0.0381^3}

\tau=27.35\ MPa

We know that 1 MPa =0.145 ksi

\tau=3.96\ ksi

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