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Bingel [31]
4 years ago
10

Imagine that you are approaching a black hole in a spacecraft. What would you see? What would happen to you?

Physics
2 answers:
aleksandr82 [10.1K]4 years ago
5 0

Answer:

When i look outside the black hole things will look warped.

Explanation:

What I would see depends on the size of the black hole.

If the black hole were small I would die before entering the black hole. I would die even before entering the event horizon. As the tidal forces of a small black are large because of the event horizon being so close to the center of the black hole my body would spaghettifi (being stretched to a small strand like spaghetti) before entering the black hole. The light would bend due to gravitational lensing.

Now, if I were to enter a supermassive black hole then i would be able to enter the event horizon because of its distance from the center of black hole. The light reaching my eyes would bend drastically. The universe outside would look as if it were warped due to gravitational lensing. Then no light would enter my eye as the mass of the black hole consumes me.

HACTEHA [7]4 years ago
3 0
As you approach the event horizon, your body would be pulled towards the black hole. It's a process called sphagettification.

Here's a quote from an article explaining this.
And gravity from the black hole is starting to pull on your feet more than your head. "The gravity wants to sort of stretch you in one direction and squeeze you in another," says Joe Polchinski.<span>
</span>
As for what you see, that is hard to explain without showing a video, at least for me, but you would see this black hole (ha) and whatever is outside starts to flatten and condense (from your POV) then you would fall into the black hole and then it's complete blackness.

But all of this is just educated guessing, and honestly, you'd be dead before anything would happen. 
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A 1000 kg mass car moved in a straight, horizontal motion, with a speed of 20m / s, when it was involved in an accident. It was
emmasim [6.3K]

Answer:

average value of the resulting force

Explanation:

The average module value of this resulting force is equivalent to 2.0. 10⁵ N.

The impulse of a force can be calculated by the product of the intensity of the force applied by the time interval in which it is applied -

I = F.Δt

Where,

F = Strength in Newtons

Δt = time interval in seconds

I = Impulse in N.s

The impulse of a force is equivalent to the variation of the amount of movement it causes in the body.

I = ΔQ

The amount of movement is a vector quantity that results from the multiplication of the mass of a body by its speed. Its direction and direction are the same as the velocity vector of the body.  

Q = m-V

As the car goes to rest after the application of force, the amount of final movement of the car is equivalent to zero.

I = 0 - mV

F. Δt = - mV

F. 0,1 = - 1000. 20

F = - 20000/0,1

F = 200,000 N

F = 2,0. 10⁵ N

6 0
3 years ago
The latent heat of vaporization of H₂O at body temperature (37°C) is 2.42 x 10⁶ J/kg. To cool the body of a 60.4-kg jogger [aver
Darya [45]

Answer:

<h2>0.094 kg</h2>

Explanation:

        Latent heat of vaporization of H_{2}O at 37°C is 2.42\times10^{6}\text{ }\frac{J}{kg}.

        When the sweat on our body evaporates, it absorbs energy from our body to overcome it's Latent heat of vaporisation. Thus our body cools down when sweat evaporates.

       So, Energy absorbed by sweat to evaporate = Energy lost by body

Specific heat capacity of human body = 3500\text{ }\frac{J}{kg\text{ }C^{o}}. Jogger weights 60.4 kg. Body temperature decreases by 1.08\text{ }C^{o}

       Energy absorbed from body = mS\Delta T=3500\times60.4\times 1.08 =228312\text{ }J

       228312\text{ }J=\text{Energy absorbed by sweat}=mC=m\times2.42\times10^{6}\\m=0.094\text{ }kg

∴ 0.094 kg of sweat has evaporated from the body.

8 0
3 years ago
Which explains why more energy is released in nuclear reactions then in chemical reactions
beks73 [17]
Nuclear reaction you are literally splitting an atom and in a chemical reaction you are not
7 0
3 years ago
In his experiment, Rutherford shot alpha particles at which type of metal?
astra-53 [7]
B.gold also known as the famous gold foil experiment 

4 0
3 years ago
Read 2 more answers
A robin flies a distance of 45963 cm. How far has it flown in kilometers?
alina1380 [7]

Answer:

0.46km

Explanation:

45963cm/100cm=459.63m/1000m=0.45963 or 0.46km

6 0
3 years ago
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