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grandymaker [24]
3 years ago
12

If I have an unknown quantity of gas at a pressure of 380 mmHg, a volume of 25 L, and a temperature of

Chemistry
1 answer:
Bess [88]3 years ago
6 0

Answer:

                     0.5077 moles

Explanation:

Data Given:

                Moles  =  n  =  <u>???</u>

                Temperature  =  T  =  300 K

                 Pressure  =  P  =  380 mmHg = 0.50 atm

                 Volume  =  V  =  25 L

Formula Used:

Let's assume that the hydrogen gas in balloon is acting as an Ideal gas, the according to Ideal Gas Equation,

                 P V  =  n R T

where;  R  =  Universal Gas Constant  =  0.082057 atm.L.mol⁻¹.K⁻¹

Solving Equation for n,

                 n  =  P V / RT

Putting Values,

                 n  =  (0.50 atm × 25 L) / (0.082057 atm.L.mol⁻¹.K⁻¹ × 300 K)

                 n  = 0.5077 moles

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Gallium is produced by the electrolysis of a solution made by dissolving gallium oxide in concentrated NaOH ( aq ) . Calculate t
Yanka [14]

Answer: Amount of Gallium = 0.127g

Explanation:

Electrolysis equation is:

Ga3+   +   3e-    ------> Ga

 To calculate the charge

t = 40.0 min = 40.0 x 60 s = 2400 s

time, t = 2400s

Q = I*t =  

= 0.22A x 2400s

= 528 C

1 mol of Ga requires 3 mol of electron

1 mol of electron = 1 Faraday =96485 C

So,1 mol of Ga requires  96485x 3= 289455 C

mol of Gallium = 528/289455 = 0.00182 mol

Molar mass of Ga = 69.72 g/mol

mass of Ga = number of moles x  molar mass

= 0.00182mol * 69.72

g/mol

= 0.127g

or you can use this direct formula

m=(current*time/Faraday's)*(molar mass/no of electrons transferred)

keeping in mind   Ga3+ + 3e- → Ga

n=3

m=(It/F)*(mew/n)

m =(0.22 x 2400/96485) x (69.72/3)

m=0.127 g

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3 years ago
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How many grams of FeCl3 are needed to make 1.5 L of a solution with a molarity of 0.450 M?
taurus [48]
Moles=concentration x volume. 1.5/1000 multiply 0.450 = 6.75x10^-4
To find the mass of fecl3, we have the formula, mass=moles x molar mass. 6.75x10^-4 x (55.8+35.5 x 3). = 0.1096g

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Explanation:

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