Answer:
8) 709.8875 J
9) The object is at 7.24375 m from the ground
10) Kinetic energy increases as the object falls.
Explanation:
We use the expression for the displacement h(t) as a function of time of an object experiencing free fall:
h(t) = hi - (g/2) t^2
hi being the initial position of the object (10m) above ground, g the acceleration of gravity (9.8 m/s^2), and t the time (in our case 0.75 seconds):
h(0.75) = 10 - 4/9 (0.75)^2 = 7.24375 m
This is the position of the 10 kg object after 0.75 seconds (answer for part 9)
Knowing this position we can calculate the potential energy of the object when it is at this height, using the formula:
U = m g h = 10kg * 9.8 (m/s^2) * 7.24375 m = 709.8875 J (answer for part 8)
Part 10)
the kinetic energy of the object increases as it gets closer to ground, since its velocity is increasing in magnitude because is being accelerated in its motion downwards.
B. It's randomness would increase
Because the Second Law of Thermodynamics states that as energy is transferred or transformed, more and more of it is wasted. It also states that there is a natural tendency of any isolated system to degenerate into a more disordered state.
let the distance of pillar is "r" from one end of the slab
So here net torque must be balance with respect to pillar to be in balanced state
So here we will have
![Mg(r - L/2) = mg(L/2 - 8)](https://tex.z-dn.net/?f=Mg%28r%20-%20L%2F2%29%20%3D%20mg%28L%2F2%20-%208%29)
here we know that
mg = 19600 N
Mg = 400,000 N
L = 20 m
from above equation we have
![400,000(r - 10) = 19,600 (10 - 8)](https://tex.z-dn.net/?f=400%2C000%28r%20-%2010%29%20%3D%2019%2C600%20%2810%20-%208%29)
![r - 10 = 0.098](https://tex.z-dn.net/?f=r%20-%2010%20%3D%200.098)
![r = 10.098 m](https://tex.z-dn.net/?f=r%20%3D%2010.098%20m)
so pillar is at distance 10.098 m from one end of the slab