How are hot spots used to track plate motion

2 answers:

8 0

A hot plate is an adjustable heating source which is ideal for heating beakers, erlenmeyer flasks, hot water baths, and other flat-bottomed containers. It is essentially an el…ectric stove top that is used in the laboratory. The temperature is adjustable (usually on a scale of 0 to 10) and there is very often a built in spinning magnetic stirrer (to be used in combination with a magnetic star bar) so that you can efficiently stir a solution while heating it. Some have computer controllers to maintain the temperature at an exact level (for instance when using a water or oil bath). A hot plate or heating mantle should always be used in place of a Bunsen burner or other open-flame source to heat a flammable liquid. See the Related Questions and Web Links to the left for more information.

wel2 years ago

7 0

Hot spots are fixed locations in the earth's mantle where heat from the earth's interior rises to the surface and produces volcanism. the earth's plates, which are slowly but constantly moving, are pierced by the uprising magma. as they move away form the hotspot, the volcanoes become dormant and are replaces by new volcanoes. The direction of the line formed from the previous volcanoes indicates the direction :)))

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Elements in a period have _____________.

ahrayia [7]

Answer:

Elements in a period have wide range of chemical properties.

Explanation:

Period is the row of chemical elements's arrangement in the periodic table. It is numbered from 1 to 7.
In period as we move towards right the atomic number of element constantly increases along with the change in chemical properties.
As we move from left towards right in period, the valence electron number regularly increases in every element.
This valence electron differs the reactivity of the elements.

6 0

3 years ago

Help! PROJECTILE PROBLEM: A 7500-kg rocket blasts off vertically from the launch pad with a constant upward acceleration of 2.25

dsp73

Here,

height at failure, h1 = 525 m,
upward acceleration, a = 2.25 m/s^2,
velocity = v m/s,

SO, 

v^2 = 2*a*h = 2*2.25*525 = 2362.5 
Now, acceleration, g = 9.8 m/s^2,

SO, 

heigt, h1 = v^2/2g = 2362.5 / 2*9.8 = 120.54 meters 
Hence,

a) 
Total height = 525+120.54 = 645.54 meters

b)
time, for h1, t = v/g = sqrt(2362.5)/9.8 = 4.96 sec

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4 0

3 years ago

Read 2 more answers

Which of the following best describes what alveolar are

Zolol [24]

Alveoli are tiny balloon shaped structures and are the smallest passageway in the respiratory system. The alveoli are only one cell thick, allowing the relatively easy passage of oxygen and carbon dioxide (CO2) between the alveoli and blood vessels called capillaries.

6 0

3 years ago

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The World-War II battleship U.S.S Massachusetts used 16-inch guns whose barrel lengths were 15 m long. The shells each of mass 1

Vaselesa [24]

Answer:

The explosive force experienced by the shell inside the barrel is 23437500 newtons.

Explanation:

Let suppose that shells are not experiencing any effect from non-conservative forces (i.e. friction, air viscosity) and changes in gravitational potential energy are negligible. The explosive force experienced by the shell inside the barrel can be estimated by Work-Energy Theorem, represented by the following formula:

$F\cdot \Delta s = \frac{1}{2}\cdot m \cdot (v_{f}^{2}-v_{o}^{2})$ (1)

Where:

$F$ - Explosive force, measured in newtons.

$\Delta s$ - Barrel length, measured in meters.

$m$ - Mass of the shell, measured in kilograms.

$v_{o}$ , $v_{f}$ - Initial and final speeds of the shell, measured in meters per second.

If we know that $m = 1250\,kg$ , $v_{o} = 0\,\frac{m}{s}$ , $v_{f} = 750\,\frac{m}{s}$ and $\Delta s = 15\,m$ , then the explosive force experienced by the shell inside the barrel is: