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vladimir1956 [14]
3 years ago
15

Which of these could be separated by distillation or filtration

Chemistry
2 answers:
Mrac [35]3 years ago
6 0
Its B- a mixture. 
Because I don't think you could separate and atom by distillation or filtration.
Actually I don't think you could separate an element by them.
I'm pretty sure compound can't be separated by them either. 
Shkiper50 [21]3 years ago
5 0

Answer: Option (B) is the correct answer.

Explanation:

A process where solute or solid particles which are present in a liquid or gas are separated out with the help of a filter medium like filter paper is known as filtration process.

For example, sand can be separated out from water by using a filter paper.

Components of a mixture can never combine chemically with each other.

Whereas, an element is a substance which contains only one type or kind of atoms.

For example, a pure zinc will contain only atoms of zinc.

A compound is defined as the substance in which different elements are chemically combined together in a fixed ratio by mass.

For example, MgSO_{4} is a compound and elements are present in 1:4 ratio.

A compound can be divided into its constituent or simpler substances.

Thus, we can conclude that a mixture could be separated by distillation or filtration.

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4 0
3 years ago
An ideal gas described by Ti=291K, Pi=1.50bar, and Vi=13.3L is heated at constant volume until P=15.0bar. It then undergoes a re
Salsk061 [2.6K]

Answer:

W=-4601.4J

Explanation:

Hello,

In this case, the steps are:

291K,1.50bar, 13.3L \rightarrow 15.0bar 13.3L,T_2\rightarrow T_2, V_2, 1.50bar\rightarrow 291K,1.50bar, 13.3L

In such a way, the work per mole (w) for that isothermal process turns out:

w=RTln(\frac{P_1}{P_2} )=8.314\frac{J}{mol*K}*291K*\frac{1.50bar}{15.0bar} \\\\w=-5570.8\frac{J}{mol}

In addition, if the moles are required, since it is an ideal gas:

n=\frac{PV}{RT}=\frac{1.50bar*13.3L}{0.083\frac{bar*L}{mol*K}*291K} =0.826mol

So the work is:

W=-5570.8\frac{J}{mol} *0.826mol=-4601.4J

Best regards.

8 0
3 years ago
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