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vladimir1956 [14]
3 years ago
15

Which of these could be separated by distillation or filtration

Chemistry
2 answers:
Mrac [35]3 years ago
6 0
Its B- a mixture. 
Because I don't think you could separate and atom by distillation or filtration.
Actually I don't think you could separate an element by them.
I'm pretty sure compound can't be separated by them either. 
Shkiper50 [21]3 years ago
5 0

Answer: Option (B) is the correct answer.

Explanation:

A process where solute or solid particles which are present in a liquid or gas are separated out with the help of a filter medium like filter paper is known as filtration process.

For example, sand can be separated out from water by using a filter paper.

Components of a mixture can never combine chemically with each other.

Whereas, an element is a substance which contains only one type or kind of atoms.

For example, a pure zinc will contain only atoms of zinc.

A compound is defined as the substance in which different elements are chemically combined together in a fixed ratio by mass.

For example, MgSO_{4} is a compound and elements are present in 1:4 ratio.

A compound can be divided into its constituent or simpler substances.

Thus, we can conclude that a mixture could be separated by distillation or filtration.

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WILL GIVE BRANLIEST TO FIRST ANSWER!!! I know the correct answer is either a or d. Can anyone explain which one it is and why? C
oee [108]

Answer: The IUPAC name of CH_3C\equiv CCH_2CH_2Cl is 5-chloro-2-pentyne

Explanation:

1. First select the longest possible carbon chain.  For the number of carbon atom, we add prefix as 'meth' for 1, 'eth' for 2, 'prop' for 3, 'but' for 4, 'pent' for 5, 'hex' for 6, 'sept' for 7, 'oct' for 8, 'nona' for 9 and 'deca' for 10.

2. The longest possible carbon chain should contain all the bonds and functional groups.

3. The numbering is done in such a way that the carbon containing the functional group or substituent gets the lowest number. Triple bond is given priority over substituent halogen.

4. The naming of alkane is done by adding the suffix -ane, alkene by adding the suffix -ene, alkyne.

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4 0
3 years ago
calculate how much acid (acetic acid) and how much conjugate base (sodium acetate) must be used to make 500ml of a 0.8m acetate
kirza4 [7]

For the desired pH of 5.76, 0.365 mol of acetate and 0.035 mol of acid are to be added

let the concentration of acetate be x

then the concentration of acid will be (0.8 - x)

pKa of acetate buffer = 4.76

pH = pKa + log([acetate]/[acid])

⇒4.76 = 4.76 + log(x/(0.8-x))

⇒log(x/(0.8-x)) = 0

⇒x/(0.8-x) = 1

⇒x = 0.4

Therefore

[acetate] = x = 0.4

[acid] = 0.8-x =0.4 M

number of mol = concentration *(volume in mL)

number of mol of acetate = 0.4*0.5

= 0.20 mol

number of mol acid = 0.4*0.5

= 0.20 mol

when desired pH = 5.76

pH = pKa + log([acetate]/[acid])

⇒5.76 = 4.76 + log(x/(0.8-x))

⇒log(x/(0.8-x)) = 1

⇒x/(0.8-x) = 10

⇒x = 8 - 10x

⇒x = 8/11

⇒x= 0.73

[acetate] = x= 0.73

[acid] = 0.8-x = 0.07 M

number of mol = concentration * (volume in mL)

number of mol acetate to be added = 0.73*0.5 = 0.365 mol

number of mol acid to be added = 0.07*0.5 = 0.035 mol

Problem based on acetic acid required to maintain a certain pH

brainly.com/question/9240031

#SPJ4

4 0
1 year ago
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