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4 years ago

7

Which atom is being researched as a possible ingredient of magnetic soap that can help clean up oil spills?

2 answers:

Ganezh [65]4 years ago

6 0

I beleive it would be Iron

Xelga [282]4 years ago

3 0

Answer:

Iron

Explanation:

Iron rich salts are under research in order to create ingredient of magnetic soap that can help clean up oil spills.

There were many other ingredients used before to remove oil spills but they are very costly and hazardous to environment. They can damage sea water and can disturb marine life.

The iron rich salts are used to creates soaps with metallic center. By this way when soap will be added to the water, the magnet will levitate iron rich bubble which can remove oil and dirt.

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A toy rocket moving vertically upward passes by a 2.0-m-high window whose sill is 8.0 m above the ground. The rocket takes 0.15

sveta [45]

Answer:

$v_i = 18.86 m/s$

Explanation:

As we know that the speed of the rocket is v1 and v2 at the bottom and top of the window

then we will have

$d = (\frac{v_1 + v_2}{2}) t$

$2 = (\frac{v_1 + v_2}{2})(0.15)$

$26.67 m/s = v_1 + v_2$

also we know that

$v_2 - v_1 = (-9.81)(t)$

$v_2 - v_1 = (-9.81)(0.15) = -1.47$

now we have

$v_2 = 12.6$

also we have

$v_1 = 14.1 m/s$

now if the sill of the window is at height 8 m from the ground then we have

$v_1^2 - v_i^2 = 2 a h$

$(14.1^2) - v_i^2 = 2(-9.81)(8)$

$v_i = 18.86 m/s$

8 0

4 years ago

Rafael is driving his car at 26 m/s. What is the shortest distance in which he can brake and stop if the coefficient of static f

Hitman42 [59]

Answer:

86.14 meters.

Explanation:

Step one:

Given data

velocity of car = 26 m/s

the coefficient of static friction between the tires and the road

µ = 0.4 (kinetic)

Let us take g = 9.81 m/s^2

Required

The distance x = distance in m

We know that

$N = Fg = mg\\\\F_\mu = -\mu N = \mu F_g = \mu mg\\\\KE = (1/2) mv^2$

W = F*x (Work is force times distance)

Step two:

Conservation of energy gives

KE = W

Substituting gives

$(1/2) mv^2 = F \mu x\\\\(1/2) mv^2 = \mu mgx\\\\mv^2 = 2 \mu mgx$

Solving for distance (x) gives

$x = mv^2 / 2 \mu mg$

Simplifying

$x = v^2 / 2 \mu g$

Substitute:

$x = v^2 / 2 \mu g$

$x= 26^2/2*0.4*9.81$

$x=676/7.848\\\\x=86.14$

Therefore, the minimum braking distance is 86.14 meters.

4 0

3 years ago

Calculate the energy needed to heat 4 kg of water from 25°C to 45°C.

inna [77]

(1 cal/g °C) x (4000 g) x (45 - 25)°C = 80000 cal = 80 kcal. So the answer is 80 kcal .

8 0

4 years ago

Read 2 more answers

The ion at the center of a silicate tetrahedron is surrounded by ________.

Naddika [18.5K]

Oxygen....................

3 0

3 years ago

Ill give 15 points to the one who helps me with this

alexandr402 [8]

Machenical number one

6 0

3 years ago