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3 years ago

For each solution below calculate the millimoles of solute.

1 answer:

8 0

A
(1.62 L) x (0.00332 mol/L NaCN) = 0.00538 mol = 5.38 mmol NaCN

B
Supposing the solvent to be water, and supposing the density of the solution is near that of pure water:
(675 g) x (5.23 x 10^-6) / (100.0875 g CaCO3/mol) = 3.53 × 10^-5 mol = 0.0353 mmol CaCO3.

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Ethylene enters a reversible, isothermal, steady-flow compressor at 1 bar and 280 K, and exits at 40 bar. Find the required comp

antiseptic1488 [7]

Answer:

Required compressor work W=8560.44 KJ/Kmol

Explanation:

Given that

Initial pressure = 1 bar

$P_1=1\ bar$

Final pressure = 40 bar

$P_2=40\ bar$

Process is isothermal and T=280 K

We know that ,work done in isothermal process given as

$W=P_1V_1\ln \dfrac{P_1}{P_2}$

given taht gas is ideal so

P V =m R T

$W=mRT\ln \dfrac{P_1}{P_2}$

R for ethylene

R=0.296 KJ/kg.K

Now by putting the values

$W=mRT\ln \dfrac{P_1}{P_2}$

$W=1\times 0.296\times 280 \ln \dfrac{1}{40}$

W= -305.73 KJ/kg

Negative sign indicates that work done on the system.

Required compressor work W=305.73 KJ/kg

Molar mass of ethylene M= 28 Kg/Kmol

So W= 305.73 x 28 KJ/Kmol

W=8560.44 KJ/Kmol

Required compressor work W=8560.44 KJ/Kmol

5 0

3 years ago

The thermite reaction reacts iron (III) oxide, Fe2O3, with aluminium powder,Al, the form aluminium oxide, Al2O3 and iron, Fe.

lara [203]

Answer:

This answer assumes that the strated "16.0g of iron" was meant to be 16.0 grams of iron(III) oxide.

Explanation:

To start, the thermite equation must be balanced.

I find:

1Fe2O3 + 2Al = 1Al2O3 + 2Fe

This tells us we need 2 moles of Al for every 1 mole of Fe2O3.

Now calculate the moles of each reactant:

Moles Fe2O3: 16.0 g/159.7 g/mole = 0.100 moles Fe2O3

Moles Al: 8.1 /26.98 g/mole = 0.300 moles Al

The balanced equation says that in order to react all of the Fe2O3 we'd need twice that amount (in moles) of the Al. (0.100 moles Fe2O3)*(2) = 0.200 moles Al.

Which of the two reactants is the limiting reagent?

We have more than enough moles of Al to react with 0.10 moles of Fe2O3. (We have 0.300 moles Al and all we need is 0.200 moles to react with the 0.10 moles of Fe2O3. Fe2O3 is the limiting reagent.

Calculate the maximum mass of iron of iron that could be formed using these quantities of reactants.

The balanced equation tells us that we will obtain 2 moles of Fe for every 1 mole of Fe2O3 consumed. Since Fe2O3 is the limiting reagent, we will assume that it completely reacts. That means 0.1 moles of Fe2O3 is reacted. Since we expect twice that many moles of Fe, we should obtain 0.200 moles of Fe. At 55.85 g/mole, we should obtain:

(0.200 moles Fe)*(55.85 g Fe/mole Fe) = 11.2 grams Fe

5 0

2 years ago

What does solubility mean

stiv31 [10]

Answer: The ability to be dissolved

Explanation:

4 0

3 years ago

What is the value of 100 ºC on the Kelvin scale? A. 100 K B. 273 K C. 373 K D. -373 K E. -300 K

insens350 [35]

Answer:

373.15 K

Explanation:

Given data:

Temperature in degree Celsius = 100°C

Temperature in kelvin scale = ?

Solution:

To convert the degree Celsius into kelvin scale we add the given degree Celsius into 273.15.

100°C +273.15 = 373.15 K

6 0

3 years ago

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Which number represents an acidic pH, 4 or 9?

katrin2010 [14]

Acids have ph less than 7 and alkali have ph more than 7

7 0

4 years ago

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