Answer:
The answer is 29 cm and 43.5 cm
Explanation:
The loop A is slack, there are three forces acting on the metre rule.
-0.9 N at 50 cm mark ,T at 70 cm mark , 2 N at x
Taking the sum of the torques about B:
By using formula:
∑τ = Iα
(-0.9 N) (50 cm − 70 cm) + (-2 N) (x − 70 cm) = 0
18 Ncm − 2 N (x − 70 cm) = 0
2 N (x − 70 cm) = 18 Ncm
x − 70 cm = 9 cm
x = 79 cm
therefore ,the distance from the center is |50 cm − 79 cm
= 29 cm.
(b) when loop B is slack, there are three forces acting on the metre rule.
-0.9 N at 50 cm mark ,T at 20 cm mark ,2 N at x
Taking the sum of the torques about A:
∑τ = Iα
(-0.9 N) (50 cm − 20 cm) + (-2 N) (x − 20 cm) = 0
-27 Ncm − 2 N (x − 20 cm) = 0
2 N (x − 20 cm) = -27 Ncm
x − 20 cm = -13.5 cm
x = 6.5 cm
Therefore the distance from the center is |50 cm − 6.5 cm
i.e. 43.5 cm
For more Torque question visit here :
brainly.com/question/6855614
#SPJ1
