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Shalnov [3]
3 years ago
10

If a 42kg rolling object slows from 11.5m/s to 3.33m/s how much work did friction do

Physics
1 answer:
geniusboy [140]3 years ago
8 0

Answer: 1608.39 J

Explanation: Given that the

mass M = 42kg

U = 11.5m/s

V = 3.33m/s

how much work did friction do

Work done = Force × distance

Work done = Ma × distance

But acceleration a = V/t

Work done = M × V/t × d

Work done = M × V × d/t

Where d/t = velocity

Therefore,

Work done = M × U × V

Work done = 42 × 11.5 × 3.33

Work done = 1608.39 J

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Answer:

Explanation:

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4 0
2 years ago
An object has a velocity of 8 m/s and a kinetic energy of 480 J. What is the mass of the object? (Formula: )
andrezito [222]

Answer:

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Explanation:

6 0
3 years ago
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cupoosta [38]

Answer:

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Explanation:

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