All categories

2 years ago

a sphere of mass 5kg and volume 2×10-5completely immersed in water find the buoyant force exerted water

Physics

1 answer:

gregori [183]2 years ago

4 0

Answer:

Buoyant force exerted water = 0.196 Newton

Explanation:

Given:

Mass of sphere ball = 5 kg

Volume = 2 x 10⁻⁵

Find:

Buoyant force exerted water

Computation:

Buoyant force exerted water = Gravity due to acceleration x volume of object x density of given liquid

Buoyant force exerted water = 9.8 x 2 x 10⁻⁵ x 1000

Buoyant force exerted water = 0.196 Newton

You might be interested in

A meter stick with a mass of 0.167 kg is pivoted about one end so it can rotate without friction about a horizontal axis. The me

SSSSS [86.1K]

Answer:

Part a)

change in potential energy is given as

$\Delta U = 0.82 J$

Part B)

angular speed of the rod is given as

$\omega = 5.42 rad/s$

Part c)

Linear speed of the end of the rod is given as

$v = 5.42 m/s$

Part d)

when a particle falls from rest to distance d = 1 m

$v = 4.42 m/s$

Explanation:

Part A)

As we know that the gravitational potential energy change is given as

$\Delta U = mgH$

$\Delta U = 0.167(9.81)(0.5)$

$\Delta U = 0.82 J$

Part B)

As we know that change in gravitational energy is equal to gain in kinetic energy

so we have

$\Delta U = \frac{1}{2}I\omega^2$

$0.82 = \frac{1}{2}(\frac{mL^2}{3})\omega^2$

$\omega^2 = \frac{6 \times 0.82}{0.167 (1)^2}$

$\omega = 5.42 rad/s$

Part c)

Linear speed of the end of the rod is given as

$v = L\omega$

$v = 5.42 m/s$

Part d)

when a particle falls from rest to distance d = 1 m

so we will have

$v = \sqrt{2gL}$

$v = \sqrt{2(9.81)(1)}$

$v = 4.42 m/s$

4 0

3 years ago

HURRY PLS WILL RATE AND THANKS AND BRAINLIEST

Rus_ich [418]

It would be the 2nd one because the higher the farther away from the equator. <span />

3 0

2 years ago

A river flows due east with a speed of 3.00 m/s relative to earth. The river is 80.0 m wide. A woman starts at the southern bank

babymother [125]

Answer:

48 m

Explanation:

As she travels at the rate of 5m/s due north, the amount of time it would take for her to cross the 80m wide river would be

t = 80 / 5 = 16 seconds

This is also the time it takes for the river to push her to the east side at the rate of 3m/s. So after 16 seconds, she would reach the opposite point at a horizontal distance from her starting of

s = 16*3 = 48 m

4 0

3 years ago

A coil formed by wrapping 65 turns of wire in the shape of a square is positioned in a magnetic field so that the normal to the

Fiesta28 [93]

Answer:

377 m

Explanation:

number of turns, N = 65

θ = 36°

B1 = 200 micro Tesla

B2 = 600 micro tesla

t = 0.4 s

induced emf, e = 80 mV

Let a be the side of the square coil.

$e=\frac{d\phi }{dt}=NA\frac{dB}{dt}\times Sinθ$

$0.080=\frac{65\times a^{2}\times Sin36\times\left ( 600 - 200 \right )\times 10^{-6}}{0.4}$

$0.080=0.038a^{2}$

a = 1.45 m

Total length of the wire, L = N x 4a = 65 x 4 x 1.45 = 377 m

Thus, the length of the wire is 377 m.

7 0

3 years ago

The kinetic energies of particles in a sample of matter are increasing. This sample is most likely

Sedaia [141]

Answer:

The sample is most likely gaining thermal energy

Explanation:

4 0

2 years ago

Read 2 more answers

a sphere of mass 5kg and volume 2×10-5completely immersed in water find the buoyant force exerted water​

a sphere of mass 5kg and volume 2×10-5completely immersed in water find the buoyant force exerted water