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olasank [31]
2 years ago
7

How would you describe the strength of the bonds that result from resonance in SO3?

Chemistry
1 answer:
Sladkaya [172]2 years ago
7 0

Answer:

All bonds are equivalent in length and strength within the molecule.

Gaseous SO3 is a trigonal planar molecule that exhibit a D3h symmetry group.

Sulfur has sp2 hybridization and it has 6 outer electrons which make the bonds with the oxygen.

Its constituent sulfur atom has an oxidation state of +6 and a formal charge of 0.

The Lewis structure is made up of one S=O double bond and two S–O dative bonds that doesn't not engage the d-orbitals. ( Thus, SO3 molecule has three double bonded oxygen to the central sulfur atom). This explains the strength.

It gaseous form had a zero electrical dipole moment  because of the 120° angle between the S-O bonds.

Explanation:

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D) [PCl5]=0.00765M,[PCl3]=0.117M,and [Cl2]=0.0.117M

Explanation:

Based on the reaction:

PCl₅(g) ⇄ PCl₃(g) + Cl₂(g)

And knowing:

Kc = [PCl₃] [Cl₂] / [PCl₅] = 1.80

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This could be written as:

[PCl₃] = X

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[PCl₅] = 0.125M - X

<em>Where X represents the moles of PCl₅ that react, </em><em>reaction coordinate.</em>

Replacing in Kc expression:

[PCl₃] [Cl₂] / [PCl₅] = 1.80

[X [X] / [0.125 - X] = 1.80

X² = 0.225 - 1.80X

0 = -X² -1.80X + 0.225

Solving for X:

X = -1.9M → False solution, there is no negative concentrations

X = 0.11735M → Right solution.

Replacing, concentrations in equilibrium are:

[PCl₃] = X

[Cl₂] = X

[PCl₅] = 0.125M - X

[PCl₃] = 0.117M

[Cl₂] = 0.117M

[PCl₅] = 0.00765M

And right option is:

<h3>D) [PCl5]=0.00765M,[PCl3]=0.117M,and [Cl2]=0.0.117M</h3>
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