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mote1985 [20]
3 years ago
8

Number 2 how many moles of propane (C3H8) are there in 6.2 g of propane? Correct answer will get brainliest.

Chemistry
1 answer:
skad [1K]3 years ago
6 0
In 1 mole of propane, there are 44 grams
so, X moles = 6.2 grams
Cross multiply: 44x = 6.2
x = 0.14 moles
(In scientific notation) The answer is B
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-Which of the following best explains how human activities can directly contribute to landslides?
Alborosie
Humans disturb the earth and because of this, the earth is weakened
8 0
3 years ago
one part of dalton's atomic theory states: compounds are formed by combinations of atoms from two or more elements. is this stat
ANEK [815]

Answer:

The statement is considered to be true

Explanation:

The statement is true because when elements chemically combine, there are interactions between their valence electrons, causing the two elements to be bonded together to form what is known as a compound.

Compounds can only be formed from interactions between two or more elements. examples include:

Hydrogen + Oxygen = H2O (water)

Sodium + Chlorine = NaCl

Note that if atoms of the same element combine, what is formed is a molecule, not a compound. Some atoms usually do this to attain stability. examples include = O2 H2 and  N2. They are oxygen molecule, hydrogen molecule, and nitrogen molecule respectively.

Compounds are only formed when different elements combine to attain electronic stability.

4 0
2 years ago
A solution was prepared by dissolving 0.800 g of sulfur S8, in 100.0 g of acetic acid, HC2H3O2. Calculate the freezing point and
Romashka [77]

<u>Answer:</u> The freezing point of solution is 16.5°C and the boiling point of solution is 118.2°C

<u>Explanation:</u>

To calculate the molality of solution, we use the equation:

Molality=\frac{m_{solute}\times 1000}{M_{solute}\times W_{solvent}\text{ in grams}}

Where,

m_{solute} = Given mass of solute (S_8) = 0.800 g

M_{solute} = Molar mass of solute (S-8) = 256.52 g/mol

W_{solvent} = Mass of solvent (acetic acid) = 100.0 g

Putting values in above equation, we get:

\text{Molality of solution}=\frac{0.800\times 1000}{256.52\times 100.0}\\\\\text{Molality of solution}=0.0312m

  • <u>Calculation for freezing point of solution:</u>

Depression in freezing point is defined as the difference in the freezing point of water and freezing point of solution.

\Delta T_f=\text{freezing point of acetic acid}-\text{Freezing point of solution}

To calculate the depression in freezing point, we use the equation:

\Delta T_f=iK_fm

or,

\text{Freezing point of acetic acid}-\text{Freezing point of solution}=iK_fm

where,

Freezing point of acetic acid = 16.6°C

i = Vant hoff factor = 1 (for non-electrolyte)

K_f = molal freezing point depression constant = 3.59°C/m

m = molality of solution = 0.0312 m

Putting values in above equation, we get:

16.6^oC-\text{freezing point of solution}=1\times 3.59^oC/m\times 0.0312m\\\\\text{Freezing point of solution}=16.5^oC

Hence, the freezing point of solution is 16.5°C

  • <u>Calculation for boiling point of solution:</u>

Elevation in boiling point is defined as the difference in the boiling point of solution and freezing point of pure solution.

The equation used to calculate elevation in boiling point follows:

\Delta T_b=\text{Boiling point of solution}-\text{Boiling point of acetic acid}

To calculate the elevation in boiling point, we use the equation:

\Delta T_b=iK_bm

or,

\text{Boiling point of solution}-\text{Boiling point of acetic acid}=iK_fm

where,

Boiling point of acetic acid = 118.1°C

i = Vant hoff factor = 1 (for non-electrolyte)

K_f = molal boiling point elevation constant = 3.08°C/m

m = molality of solution = 0.0312 m

Putting values in above equation, we get:

\text{Boiling point of solution}-118.1^oC=1\times 3.08^oC/m\times 0.0312m\\\\\text{Boiling point of solution}=118.2^oC

Hence, the boiling point of solution is 118.2°C

8 0
3 years ago
Which statement about spontaneous and nonspontaneous processes is correct? Spontaneous processes are favored by a decrease in H,
Marina86 [1]
I believe your answer would be the first one

hope this helps
7 0
3 years ago
Read 2 more answers
Is this right ? if it’s wrong correct me
Dimas [21]
You can go to a website about that it will give you the answers
4 0
3 years ago
Read 2 more answers
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