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Naddik [55]
3 years ago
7

This ether, C4H8O, can be produced by slow distillation from an acidic solution of 1,4-butanediol, HOCH2CH2CH2CH2OH. It gives a

negative test for C-C double bonds. Propose a structure for this compound.

Chemistry
1 answer:
horrorfan [7]3 years ago
6 0

Answer:

Tetrahydrofuran

Explanation:

Since the compound tested negative for C-C double bond, it must be a cyclic ether. Cyclic ethers have the oxygen atom attached to a ring. It is important to note that in a cyclic compound, one carbon atom is only bonded to two hydrogen atoms. Hence there are four carbon atoms in the compound, eight hydrogen atoms and one oxygen atom. This corresponds to the structure of tetrahydrofuran. Its structure is shown in the image attached.

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For the following reaction, 22.6 grams of nitrogen monoxide are allowed to react with 4.64 grams of hydrogen gas . nitrogen mono
antiseptic1488 [7]

Answer:

- 10.5 g of N₂

- Limiting reagent: NO

- 3.13 g of H₂ remains

Explanation:

First of all we state the reaction: 2NO(g) + 2H₂(g) → 2H₂O(l) + N₂(g)

We need to find out the limiting reactant and the excess reagent

Ratio in the reactants is 2:2. Let's convert the mass to moles:

22.6 g / 30 g/mol = 0.753 moles of NO

4.64 g / 2 g/mol = 2.32 moles of H₂

Certainly the limiting reagent is the NO and the excess reactant is the hydrogen:

- For 0.753 moles of NO, we need 0.753 moles of H₂ (we have 2.32 moles)

- For 2.32 moles of H₂, we need 2.32 moles of NO (and we don't have enough NO, because we only have 0.753 moles)

As the H₂ is the excess reagent, some moles still remains after the reaction is complete → 2.32 mol - 0.753 mol = 1.567 moles

We convert the moles to mass: 1.567 mol . 2g /1mol = 3.13 g of H₂ remains

As the NO is the limiting reagent, we can work with the equation:

We propose this rule of three: 2 moles of NO can produce 1 mol of N₂

Then, 0.753 moles of NO must produce (0.753 . 1) /2 = 0.376 moles of N₂

We convert the moles to mass 0.376 mol . 28 g / 1 mol = 10.5 g

3 0
3 years ago
Which metal will more easily lose an electron sodium or potassium?
sergey [27]
<span>The metal that would more easily lose an electron would be potassium. It is more reactive than sodium. Also, looking on the periodic table, </span><span>from top to bottom for groups 1 and 2, reactivity increases. So, it should be potassium. Hope this answers the question. Have a nice day.</span>
7 0
3 years ago
What causes dipole interactions?
Marina CMI [18]
Attraction between polar molecules
8 0
2 years ago
Complete each statement to identify the form of asexual reproduction.
Mrrafil [7]

Spore formation is a form of asexual reproduction used by mushrooms and molds.

During  budding, the offspring grows from the body of the parent.

Fragmentation is a form of asexual reproduction that must be followed by regeneration.

Explanation:

Asexual reproduction is the type of reproduction where the gamete formation and fusion have no relevance or existence. It functions on the process of somatic cell division via mitosis and the offsprings are identical to their parents.

The spore formation occurs in fungi through sporangia, bursting open to shed spores, forming into a new young ones. Budding occurs out as an outgrowth of the parent and attains maturity and separates. Fragmentation is the process where the parents fall apart into pieces and regeneration follows.

8 0
3 years ago
Read 2 more answers
How many moles of Ca(OH)2 are in 3.5kg of Ca(OH)2? Answer in units of mole
Kobotan [32]
First, you need to convert kg to g. 
So, 1 kg =1000g.
3.5 x 1000 = 3500g Ca(OH)2

We need to know the molar mass of Ca(OH)2. 
Ca= 40.08 g
O=2(15.999)
H=2(1.0079)

Add them all together and you get 74.0938 g.

Put it in the formula from mass to moles. 

# of moles = grams Ca(OH)2 x 1 mol Ca(OH)2
                                                  --------------------
                                                  molar mass Ca(OH)2

3500 g Ca(OH)2 x 1 mol Ca(OH)2
                              ---------------------
                             74.0938 g Ca(OH)2

So divide 1/74.0938 and multiply by 3500.

You will get about 47.24 moles Ca(OH)2.

Hope this helps! :)
7 0
3 years ago
Read 2 more answers
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