This ether, C4H8O, can be produced by slow distillation from an acidic solution of 1,4-butanediol, HOCH2CH2CH2CH2OH. It gives a
negative test for C-C double bonds. Propose a structure for this compound.
1 answer:
Answer:
Tetrahydrofuran
Explanation:
Since the compound tested negative for C-C double bond, it must be a cyclic ether. Cyclic ethers have the oxygen atom attached to a ring. It is important to note that in a cyclic compound, one carbon atom is only bonded to two hydrogen atoms. Hence there are four carbon atoms in the compound, eight hydrogen atoms and one oxygen atom. This corresponds to the structure of tetrahydrofuran. Its structure is shown in the image attached.
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Answer:
Partial pressure of dinitrogen tetroxide after equilibrium is reached the second time is 0.82 atm.
Explanation:
Initially
3.0 atm 0
At equilibrium
(3.0-2p) p
Equilibrium partial pressure of
p = 0.45 atm
The value of equilibrium constant wil be given by :
After addition of 1.5 atm of nitrogen dioxide gas equilibrium reestablishes it self :
After adding 1.5 atm of :
(2.1+1.5) atm 0.45 atm
At second equilibrium:'
(3.6-2P) (0.45+P)
The expression of equilibrium can be written as:
Solving for P:
P = 0.37 atm
Partial pressure of dinitrogen tetroxide after equilibrium is reached the second time:
= (0.45+P) atm = (0.45 + 0.37 )atm = 0.82 atm
Partial pressure of dinitrogen tetroxide after equilibrium is reached the second time is 0.82 atm.