Answer:
B) t = 1.83 [s]
A) y = 16.51 [m]
Explanation:
To solve this problem we must use the following equation of kinematics.
![v_{f} =v_{o} -g*t](https://tex.z-dn.net/?f=v_%7Bf%7D%20%3Dv_%7Bo%7D%20-g%2At)
where:
Vf = final velocity = 0
Vo = initial velocity = 18 [m/s]
g = gravity acceleration = 9.81 [m/s²]
t = time [s]
Note: the negative sign in the above equation means that the acceleration of gravity is acting in the opposite direction to the motion.
A) The maximum height is reached when the final velocity of the ball is zero.
0 = 18 - (9.81*t)
9.81*t = 18
t = 18/9.81
t = 1.83 [s], we found the answer for B.
Now using the following equation.
![y = y_{o} + v_{o}*t - 0.5*g*t^{2}\\](https://tex.z-dn.net/?f=y%20%3D%20y_%7Bo%7D%20%2B%20v_%7Bo%7D%2At%20-%200.5%2Ag%2At%5E%7B2%7D%5C%5C)
where:
y = elevation [m]
Yo = initial elevation = 0
y = 18*(1.83) - 0.5*9.81*(1.83)²
y = 16.51 [m]
Answer:
![E=35921.96N/C](https://tex.z-dn.net/?f=E%3D35921.96N%2FC)
Explanation:
From the question we are told that:
Radius ![r=0.321mm](https://tex.z-dn.net/?f=r%3D0.321mm)
Charge Density ![\mu=0.100](https://tex.z-dn.net/?f=%5Cmu%3D0.100)
Distance
Generally the equation for electric field is mathematically given by
![E=\frac{mu}{2\pi E_0r}](https://tex.z-dn.net/?f=E%3D%5Cfrac%7Bmu%7D%7B2%5Cpi%20E_0r%7D)
![E=\frac{0.100*10^{-6}}{2*3.142*8.86*10^{-12}*5*10^{-2}}](https://tex.z-dn.net/?f=E%3D%5Cfrac%7B0.100%2A10%5E%7B-6%7D%7D%7B2%2A3.142%2A8.86%2A10%5E%7B-12%7D%2A5%2A10%5E%7B-2%7D%7D)
![E=35921.96N/C](https://tex.z-dn.net/?f=E%3D35921.96N%2FC)
True
It is True I took the test