As the volume of the confined gas decreases at the constant temperature, the pressure exerted by the gas increases.
H₂O₂ + 2FeSO₄ + H₂SO₄ → Fe₂(SO₄)₃ + 2H₂O
H₂O₂ + 2H⁺ + 2e⁻ → 2H₂O k=1
Fe²⁺ → Fe³⁺ + e⁻ k=2
H₂O₂ + 2H⁺ + 2Fe²⁺ → 2H₂O + 2Fe³⁺
Concentration :
196 g/L and 4 N
<h3> </h3><h3>Further explanation</h3>
The concentration of a substance can be expressed in several quantities such as moles, percent (%) weight / volume,), molarity, molality, parts per million (ppm) or mole fraction. The concentration shows the amount of solute in a unit of the amount of solvent.
500 cc of 2M H₂SO₄
V = 500 cc = 0.5 L
mol H₂SO₄

mass H₂SO₄ (MW = 98 g/mol)

concentration in g/L :

concentration in normality
Relationship between normality and molarity
N = M x n (n=valence , amount of H⁺ or OH⁻)
so :

Answer: Thomson - C
Rutherford - B
Bohr - A
Explanation: I just took the quiz