<em><u>Invertebrat</u></em><em><u>e</u></em><em><u> </u></em><em><u>means</u></em><em><u> </u></em><em><u>those</u></em><em><u> </u></em><em><u>organism</u></em><em><u> </u></em><em><u>which</u></em><em><u> </u></em><em><u>doesnot</u></em><em><u> </u></em><em><u>have</u></em><em><u> </u></em><em><u>backbone</u></em><em><u> </u></em><em><u>in</u></em><em><u> </u></em><em><u>their</u></em><em><u> </u></em><em><u>body</u></em><em><u> </u></em><em><u>.</u></em><em><u>Some</u></em><em><u> </u></em><em><u>of</u></em><em><u> </u></em><em><u>t</u></em><em><u>he</u></em><em><u> </u></em><em><u>examples</u></em><em><u> </u></em><em><u>are</u></em><em><u>:</u></em>
<em><u>1</u></em><em><u>.</u></em><em><u>S</u></em><em><u>p</u></em><em><u>i</u></em><em><u>d</u></em><em><u>e</u></em><em><u>r</u></em>
<em><u>2</u></em><em><u>.</u></em><em><u>e</u></em><em><u>a</u></em><em><u>r</u></em><em><u>t</u></em><em><u>h</u></em><em><u>w</u></em><em><u>o</u></em><em><u>r</u></em><em><u>m</u></em>
<em><u>3</u></em><em><u>.</u></em><em><u>S</u></em><em><u>t</u></em><em><u>a</u></em><em><u>r</u></em><em><u>f</u></em><em><u>i</u></em><em><u>s</u></em><em><u>h</u></em>
<em><u>4</u></em><em><u>.</u></em><em><u>S</u></em><em><u>e</u></em><em><u>a</u></em><em><u> </u></em><em><u>urchins</u></em><em><u>.</u></em>
<em><u>hope</u></em><em><u> </u></em><em><u>this</u></em><em><u> </u></em><em><u>will</u></em><em><u> </u></em><em><u>help</u></em><em><u> </u></em><em><u>u</u></em><em><u> </u></em><em><u>a</u></em><em><u> </u></em><em><u>lot</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em>
Answer:

Explanation:
This is a uniformly accelerated motion, so we can determine the deceleration of the car by using a suvat equation:

where
v is the final velocity
u is the initial velocity
a is the acceleration
s is the distance covered
For the car in this problem,
u = 27.8 m/s
v = 0
s = 17 m
Solving for a, we find the acceleration:

<span>As long as both mirrors are set at 45% and the same size then you see the same as is reflected in the upper mirror </span>
<span>Put a lens in the middle of the tube </span>
<span>? </span>
<span>We use mirrors when we drive cars ect </span>
<span>Normally they are set across from a concealed entrance or one that is hard to see both ways like the inside of a hairpin bend. Sometimes only to help in one direction. </span>
<span>Sonar which is sound waves that are sent out at a set rate then reflected by objects. The longer the gap between the two the further away it is, They still use periscopes to target boats though. </span>
<span>The periscope can only reflect what is outside so if you could see it because there is enough light then Yes. If you could not see it because it is dark then No unless you get into Info-Red light or Image Intensifying systems as well </span>
Answer:
471392.4 N
Explanation:
From the question,
Just before contact with the beam,
mgh = Fd.................... Equation 1
Where m = mass of the beam, g = acceleration due to gravity, h = height. F = average Force on the beam, d = distance.
make f the subject of the equation
F = mgh/d................ Equation 2
Given: m = 1900 kg, h = 4 m, d = 15.8 = 0.158 m
Constant: g = 9.8 m/s²
Substitute into equation 2
F = 1900(4)(9.8)/0.158
F = 471392.4 N
Answer:
mass and distance
Explanation:
force is mass while motion can also be regard as distance or movement