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adelina 88 [10]
4 years ago
13

Which of the following statements is accurate? A. Compressions and rarefactions occur throughout a transverse wave. B. The wavel

ength of both transverse and longitudinal waves is measured parallel to the direction of the travel of the wave. C. Amplitude of longitudinal waves is measured at right angles to the direction of the travel of the wave and represents the maximum distance the molecule has moved from its normal position. D. Sound waves passing through the air will do so as transverse waves, which vibrate vertically and still retain their horizontal positions.
Physics
2 answers:
suter [353]4 years ago
6 0

Answer:

B

Explanation:

Eduardwww [97]4 years ago
4 0
<h3><u>Answer;</u></h3>

<em>B. The wavelength of both transverse and longitudinal waves is measured parallel to the direction of the travel of the wave.</em>

<h3><u>Explanation;</u></h3>
  • <em><u>Longitudinal waves are waves in which the vibration of particles is parallel to the direction of the wave motion.</u></em> The vibration of particles generates regions known as compressions and rarefactions. Therefore<em> </em><u><em>the wavelength is the distance between two successive rarefactions or compressions.</em></u>
  • <u><em>Transverse waves on the other hand are those waves in which the vibration of particles is perpendicular to the direction of the wave motion. </em></u>The vibration of particles generates regions of maximum displacement called crests and regions of minimum displacement called troughs. Thus, <em><u>the wavelength is the distance between two successive crests or troughs.</u></em>
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Pressure of gas is 13.6 cm of hg what does it means​
vlada-n [284]

Explanation:

13 cmHg (centimeters of mercury) is the pressure at the bottom of a column of mercury 13 cm deep.  It is the equivalent of about 17.3 kPa or 2.5 psi.

5 0
3 years ago
A hill is 132 m long and makes an angle of 12.0 degrees with the horizontal. As a 54 kg jogger runs up the hill, how much work d
TEA [102]

Answer:

14523.55J

Explanation:

The work done by the jogger against gravity is given by the following equation;

W=mgh.................(1)

where m is the mass, g is acceleration due to gravity taken as 9.8m/s^2 and h is the height of the hill.

Since the length of the hill is 132m and it is inclined at 12 degrees to the horizontal, the height is thus given as follows;

h=132sin12^o\\h=27.44m

Substituting this into equation (1) with all other necessary parameters, we obtain the following;

W=54*9.8*27.44\\W=14523.55J

4 0
3 years ago
A gymnast is swinging on a high bar. The distance between his waist and the bar is 0.905 m, as the drawing shows. At the top of
Citrus2011 [14]

Answer:

5.959 m/s

Explanation:

m = Mass of gymnast

u = Initial velocity

v = Final velocity

h_i = Initial height

h_f = Final height

From conservation of Energy

\frac{1}{2}mv^2+mgh_f=\frac{1}{2}mu^2+mgh_i\\\Rightarrow\frac{1}{2}mv^2+mg0=\frac{1}{2}m0^2+mgh_i\\\Rightarrow \frac{1}{2}mv^2=mgh_i\\\Rightarrow v=\sqrt{2gh_i}

h_i=2r

v=\sqrt{4gr}\\\Rightarrow v=\sqrt{4\times 9.81\times 0.905}\\\Rightarrow v=5.959\ m/s

Velocity of gymnast at bottom of swing is 5.959 m/s

5 0
4 years ago
Which players are usually the tallest on their team, and stay close to the basket so they can shoot and rebound the ball?
alexdok [17]

Answer:

Center

Explanation:

The center is the tallest player on each team, playing near the basket. On offense, the center tries to score on close shots and rebound. But on defense, the center tries to block opponents' shots and rebound their misses.

7 0
3 years ago
A (B + 25.0) g mass is hung on a spring. As a result, the spring stretches (8.50 A) cm. If the object is then pulled an addition
Morgarella [4.7K]

Answer:

Time period of the osculation will be 2.1371 sec

Explanation:

We have given mass m = (B+25)

And the spring is stretched by (8.5 A )

Here A = 13 and B = 427

So mass m = 427+25 = 452 gram = 0.452 kg

Spring stretched x= 8.5×13 = 110.5 cm

As there is additional streching of spring by 3 cm

So new x = 110.5+3 = 113.5 = 1.135 m

Now we know that force is given by F = mg

And we also know that F = Kx

So mg=Kx

K=\frac{mg}{x}=\frac{0.452\times 9.8}{1.135}=3.90N/m

Now we know that \omega =\sqrt{\frac{K}{m}}

So \frac{2\pi }{T} =\sqrt{\frac{K}{m}}

\frac{2\times 3.14 }{T} =\sqrt{\frac{3.90}{0.452}}

T=2.1371sec

8 0
3 years ago
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