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4 years ago

On heating from low temperature at 1 atm of pressure which substance is most likely to sublime rather than melt?

1 answer:

5 0

Since the choices are not given, I can't give an exact answer. Sublimation is the physical change occurring from solid to gas. This is very rare because the molecular arrangement of a solid and gas are opposite to each other. Thus, it depends on the properties of the substance. For example, napthalene could sublime at room temperature.

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A truck with a heavy load has a total mass of 7100 kg. It is climbing a 15∘ incline at a steady 15 m/s when, unfortunately, the

Andrej [43]

Answer:

The load has a mass of 2636.8 kg

Explanation:

Step 1 : Data given

Mass of the truck = 7100 kg

Angle = 15°

velocity = 15m/s

Acceleration = 1.5 m/s²

Mass of truck = m1 kg

Mass of load = m2 kg

Thrust from engine = T

Step 2:

⇒ Before the load falls off, thrust (T) balances the component of total weight downhill:

T = (m1+m2)*g*sinθ

⇒ After the load falls off, thrust (T) remains the same but downhill component of weight becomes m1*gsinθ .

Resultant force on truck is F = T – m1*gsinθ

F causes the acceleration of the truck: F= m*a

This gives the equation:

T – m1*gsinθ = m1*a

T = m1(a + gsinθ)

Combining both equations gives:

(m1+m2)*g*sinθ = m1*(a + gsinθ)

m1*g*sinθ + m2*g*sinθ =m1*a + m1*g*sinθ

m2*g*sinθ = m1*a

Since m1+m2 = 7100kg, m1= 7100 – m2. This we can plug into the previous equation:

m2*g*sinθ = (7100 – m2)*a

m2*g*sinθ = 7100a – m2a

m2*gsinθ + m2*a = 7100a

m2* (gsinθ + a) = 7100a

m2 = 7100a/(gsinθ + a)

m2 = (7100 * 1.5) / (9.8sin(15°) + 1.5)

m2 = 2636.8 kg

The load has a mass of 2636.8 kg

6 0

3 years ago

A 1000 kg elevator accelerates upward at 1.0 m/s2 for 10 m, starting from rest. a. How much work does gravity do on the elevator

Ivenika [448]

Here you go mate. Hope it helps u. Pls follow me in reddit lol username: RobloxNoob2006

5 0

3 years ago

The diagram shows a position-time graph What is the displacement of the object

algol13

The object is moving, so at different times, it has different displacement. I'm guessing that you probably want to know the displacement at the end of the time on the graph ... 5 seconds.

Displacement is the distance and the direction FROM (the position at the beginning) TO (the position at the end).

At the beginning ... time=0 ... the position is 1 meter.

At the end ... time=5 ... the position is zero.

The distance FROM the beginning TO the end is (zero - 1m) . That's <em>-1m </em>.

5 0

3 years ago

The world's largest wind turbine has blades that are 80 m long and makes 1 revolution every 5.7 seconds. What is the velocity fo

Arturiano [62]

Answer:

The velocity of the blades is 88.185 m/s.

Explanation:

Given;

length of the blade, r = 80 m

angular speed, ω = 1 rev per 5.7 seconds

The velocity of the blades is calculated by applying the following circular motion equation that relates linear velocity (V) and angular speed (ω);

$V = \omega r\\\\V = (\frac{1 \ rev}{5.7 \ s} \times \frac{2 \pi \ rad}{ 1 \ rev} )(80 \ m)\\\\V = 88.185 \ m/s$

Therefore, the velocity of the blades is 88.185 m/s.

7 0

3 years ago

Let two objects of equal mass m collide. Object 1 has initial velocityv, directed to the right, and object 2 isinitially station

3241004551 [841]

<span>Our equation 1 would be
m*v=M*V1+m*V2
v=V1+V2
v-V1=V2

the equation 2 would look like this
</span>V^2=V1^2+V2^2
V^2-V1^2=V2^2
(V-V1)*(V+V1)=V2^2Dividing with the 1
V+V1=V2

8 0

3 years ago