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Ivanshal [37]
3 years ago
14

15 POINTS!!!

Chemistry
2 answers:
gladu [14]3 years ago
8 0

<u>At 60° C</u>. The higher the temperature, the higher the kinetic energy.

lawyer [7]3 years ago
7 0

<em>Answer:</em>

  • At 60 centigrade, the kinetic energy of the substance will be greatest.

<em>Explanation:</em>

As we know, the kinetic energy of substance is directly proportional to Temperature.

The total Kinetic energy can be calculated as follow

                                                K.E = 3/2 n.R.T

From the equations, it is cleared that Temperature is directly proportional to temperature.

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Answer:

The significance of "Er" in the diagram is :

B.) Threshold energy for reaction

Explanation:

Threshold energy : It is total amount of energy required by the reactant molecule to reach the transition state .

Activation energy : It is the excess energy absorbed by the molecules to reach the transition state.

<u>Activation Energy = Threshold Energy - Average Kinetic Energy</u>

<u>This means Activation energy decreases on increasing kinetic energy</u>

On increasing Temperature average kinetic energy of the molecule increases which reduces the activation energy and the reaction occur faster in that case.

Catalyst also reduces the Activation energy.

<u>Er = Threshshold energy for reaction at 30 degree</u>

<u>Ea = Activation Energy</u>

<u>The given figure shows that the threshold energy decreases on increasing the temperature</u>

<u>Only the molecule having energy greater than Er can react to form product</u>

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2 years ago
Materials expand when heated. Consider a metal rod of length L0 at temperature T0. If the temperature is changed by an amount ΔT
marysya [2.9K]

Answer:

(a) The length at temperature 180°C is 40.070 cm

(b) The length at temperature 90°C is 64.976 inches

(c) L(T, α) = 60·α·T - 9000·α + 60

Explanation:

(a) The given parameters are

The thermal expansion coefficient, α for steel = 1.24 × 10⁻⁵/°C

The initial length of the steel L₀ = 40 cm

The initial temperature, t₀ = 40°C

The length at temperature 180°C = L

Therefore, from the given relation, for change in length, ΔL, we have;

ΔL = α × L₀ × ΔT

The amount the temperature changed ΔT = 180°C - 40°C = 140°C

Therefore, the change in length, ΔL, is found as follows;

ΔL = α × L₀ × ΔT = 1.24 × 10⁻⁵/°C × 40 × 140°C = 0.07 cm

Therefore, L =  L₀ + ΔL = 40 + 0.07 = 40.07 cm

The length at temperature 180°C = 40.07 cm

(b) Given that the length at T = 120°C is 65 in., we have;

The temperature at which the new length is sought = 90°C

The amount the temperature changed ΔT = 90°C - 120°C = -30°C

ΔL = α × L₀ × ΔT = 1.24 × 10⁻⁵/°C × 65 × -30°C = -0.024375 inches

The length, L at 90°C is therefore, L = L₀ + ΔL = 65 - 0.024375 = 64.976 in.

The length at temperature 90°C = 64.976 inches

(c) L = L₀ + ΔL  = L₀ +  α × L₀ × ΔT = L₀ +  α × L₀ × (T - T₀)

Therefore;

L = 60 +  α × 60 × (T - 150°C)

L = 60 + α × 60 × T - 9000 × α

L(T, α) = 60·α·T - 9000·α + 60

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