Answer:
Zn(s) produces H₂ when is added to a strong acid solution
Explanation:
Look at this example:
2Zn (s) + 2HCl (aq) → 2ZnCl (aq) + H₂ (g)
It is a redox reaction, where the zinc is oxidized and the H, reducted.
Zn → Zn⁺ + 1e⁻
2H⁺ + 1e⁻ → H₂
I have included the work and the process which is easiest for me to balance chemical equations. I hope it helps!
I would say #3 I’m sorry if it’s wrong tho
Hello!
To solve this problem we need to know the value of
pKa for HC₂H₃O₂ (Acetic Acid) which is
4,76. Now we can apply the
Henderson-Hasselbach equation, as follows (assuming that HC₂H₃O₂ concentration is 0,22M):
![pH=pKa + log ( \frac{KC_2H_3O_2}{HC_2H_3O_2} )=4,76 + log ( \frac{0,122M}{0,22M} )=4,50](https://tex.z-dn.net/?f=pH%3DpKa%20%2B%20log%20%28%20%5Cfrac%7BKC_2H_3O_2%7D%7BHC_2H_3O_2%7D%20%29%3D4%2C76%20%2B%20log%20%28%20%5Cfrac%7B0%2C122M%7D%7B0%2C22M%7D%20%29%3D4%2C50)
So, the pH for this buffer solution of HC₂H₃O₂ and KC₂H₃O₂ is
4,50Have a nice day!