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bogdanovich [222]
4 years ago
7

The heat (or enthalpy) of fusion for ice is 0.334 kj/g.

Chemistry
1 answer:
grandymaker [24]4 years ago
8 0
According to this formula:

Q = ΔH fusion * mass (g)

when we have:

ΔH fusion (the heat (or enthalpy) of fusion = 0.334 kJ/g

and mass of ice = 22.4 g 

so by substitution, we can get the energy (Q) required to melt this mass of ice:

∴ Q = 0.334KJ/g * 22.4 g 

       = 7.48 KJ

∴ the energy required to melt 22.4 g of ice is = 7.48 KJ
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